Oh, dude, let's break it down. So, 621 is divisible by 2 because it's an even number. It's not divisible by 3 because the sum of its digits isn't a multiple of 3. It's not divisible by 4 because the last two digits aren't divisible by 4. It's not divisible by 5 because it doesn't end in 0 or 5. It's not divisible by 6 because it's not divisible by both 2 and 3. And it's not divisible by 10 because it doesn't end in 0. So, like, that's the scoop!
It is not. 621 is divisible by 3, not the other way round.
621 is divisible by these numbers: 1, 3, 9, 23, 27, 69, 207, 621.
yes
It is divisible by 2 and 3. It isn't divisible by 5 and 10.
9 is divisible by 3 10 is divisible by 2, 5 and 10. Everything else, no.
In order for a number to be divisible by 6, it must be divisible by both 3 and 2. 621 is divisible by 3, but not by 2. In other words, 6 will not go into 621 evenly. The answer will be a decimal.
It is not. 621 is divisible by 3, not the other way round.
621 is divisible by these numbers: 1, 3, 9, 23, 27, 69, 207, 621.
yes
It is divisible by 2 and 3. It isn't divisible by 5 and 10.
Yes, it is divisible by 2, 3 and 9, but is not exactly divisible by 5 or 10.
It is evenly divisible by 2 and 10 but not by 3 and 9.
9 is divisible by 3 10 is divisible by 2, 5 and 10. Everything else, no.
20 is divisible by 2, 5 and 10. It is not exactly divisible by 3 or 9.
It is divisible by 2, 5 and 10, but not 3 and 9.
It is divisible by 2 & 3. It is not divisible by 5, 9 & 10. 534 is even → divisible by 2 5 + 3 + 4 = 12 → divisible by 3 534 does not end in 0 or 5 → not divisible by 5 5 + 3 + 4 = 12 → not divisible by 9 534 does not end in 0 → not divisible by 10
No since only numbers in which its sum can be divisible by 3 is divisible by 3. 2 + 4 + 4 is 10, and 10 is not divisible by 3.