Oh, dude, let's break it down. So, 621 is divisible by 2 because it's an even number. It's not divisible by 3 because the sum of its digits isn't a multiple of 3. It's not divisible by 4 because the last two digits aren't divisible by 4. It's not divisible by 5 because it doesn't end in 0 or 5. It's not divisible by 6 because it's not divisible by both 2 and 3. And it's not divisible by 10 because it doesn't end in 0. So, like, that's the scoop!
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To determine if 621 is divisible by 2, we look at the last digit which is 1, and since it is odd, 621 is not divisible by 2. To check divisibility by 3, we sum the digits: 6 + 2 + 1 = 9, which is divisible by 3, so 621 is divisible by 3. For divisibility by 4, we examine the last two digits, which are 21, and since 21 is not divisible by 4, 621 is not divisible by 4. Since the last digit is not 0 or 5, 621 is not divisible by 5. 621 is not divisible by 6 as it is not divisible by both 2 and 3 simultaneously. Lastly, since 621 ends in 1, it is not divisible by 10.
It is not. 621 is divisible by 3, not the other way round.
621 is divisible by these numbers: 1, 3, 9, 23, 27, 69, 207, 621.
yes
It is divisible by 2 and 3. It isn't divisible by 5 and 10.
9 is divisible by 3 10 is divisible by 2, 5 and 10. Everything else, no.