621 is divisible by these numbers: 1, 3, 9, 23, 27, 69, 207, 621.
It is not. 621 is divisible by 3, not the other way round.
As 4 is less than 621, 4 is not divisible by 621. Nor is 621 divisible by 4: 4 is even and all multiples of 4 are even, 621 is odd and so cannot be a multiple of 4. To check divisibility by 4, if the the last 2 digits are divisible by 4, the original number is divisible by 4. For 621, the last 2 digits are 21 and 21 is not divisible by 4, thus 621 is not divisible by 4; nor is 622 since the last 2 digits 22 is not divisible by 4.
Oh, dude, let's break it down. So, 621 is divisible by 2 because it's an even number. It's not divisible by 3 because the sum of its digits isn't a multiple of 3. It's not divisible by 4 because the last two digits aren't divisible by 4. It's not divisible by 5 because it doesn't end in 0 or 5. It's not divisible by 6 because it's not divisible by both 2 and 3. And it's not divisible by 10 because it doesn't end in 0. So, like, that's the scoop!
yes
621 is divisible by 9?
621 is divisible by these numbers: 1, 3, 9, 23, 27, 69, 207, 621.
621 is not divisible by 6.
It is not. 621 is divisible by 3, not the other way round.
As 4 is less than 621, 4 is not divisible by 621. Nor is 621 divisible by 4: 4 is even and all multiples of 4 are even, 621 is odd and so cannot be a multiple of 4. To check divisibility by 4, if the the last 2 digits are divisible by 4, the original number is divisible by 4. For 621, the last 2 digits are 21 and 21 is not divisible by 4, thus 621 is not divisible by 4; nor is 622 since the last 2 digits 22 is not divisible by 4.
no because 621 is odd.
In order for a number to be divisible by 6, it must be divisible by both 3 and 2. 621 is divisible by 3, but not by 2. In other words, 6 will not go into 621 evenly. The answer will be a decimal.
It is composite. It is divisible by 3, 9, 23, 27, 69, and 207.
No.
Oh, dude, let's break it down. So, 621 is divisible by 2 because it's an even number. It's not divisible by 3 because the sum of its digits isn't a multiple of 3. It's not divisible by 4 because the last two digits aren't divisible by 4. It's not divisible by 5 because it doesn't end in 0 or 5. It's not divisible by 6 because it's not divisible by both 2 and 3. And it's not divisible by 10 because it doesn't end in 0. So, like, that's the scoop!
No, any number which is perfectly divisible by 9 has its digits equal to a multiple of 9. The closest multiples of 9 to 615 are 612 and 621. (68 x 9 and 69 x 9 respectively).
yes