Neither one.
12 is a multiple of 6 and 1 is a factor of 12 and so 12+1 = 13
To find the smallest natural number that is a multiple of 13 and divisible by both 4 and 6, we first determine the least common multiple (LCM) of 4 and 6, which is 12. Next, we need to find the smallest multiple of 13 that is also a multiple of 12. The smallest multiple of 13 is 13 itself, but 13 is not divisible by 12. The smallest multiple of 13 that is also divisible by 12 is 156, as ( 156 = 13 \times 12 ). Therefore, the answer is 156.
The LCM of 12 and 13 is 156.
It is: 12+1 = 13
The lowest common multiple of 12 and 13 is 156
686 × 1 = 686 196 × 3.5 = 686 ∴ The least common multiple of 686 and 196 is 686. Hope can help you:)
The LCM of 375 and 686 is 257,250.
12 is a multiple of 6 and 1 is a factor of 12 and so 12+1 = 13
If the last digit doubled subtracted from the rest is a multiple of 7, the whole number is divisible by 7. Example: 686 68 - 12 = 56 56 is divisible by 7. 686 is divisible by 7.
Least common multiple of 5 and 12 and 13 is 780.
The Least Common Multiple (LCM) for 4 12 13 is 156.
The LCM of 12 and 13 is 156.
It is: 12+1 = 13
The Least Common Multiple (LCM) for 12 13 is 156.
The lowest common multiple of 12 and 13 is 156
The Least Common Multiple (LCM) for 13 2 3 12 is 156.
Yes, 13*12=156