6n2 + 16n can be factorised to give 2n(3n + 8) so the highest factor is 2n.
(3m+2n)(m+3n)
4 = -5n + 6n2 if you want to solve for n: 6n2 - 5n - 4 = 0 (3n - 4)(2n + 1) = 0 3n - 4 = 0, n = 4/3 2n + 1 = 0, n = -1/2 n = {-1/2, 4/3}
Composite. It is divisible by 3 for any n.
6n2+6n+1
6n2
Factors of 6 are either 1 & 6 or 2 & 3, those of 4 are either 1 & 4 or 2 & 2. The only combination which gives the required sum and product is (2n + 1)(3n - 4)
6(n - 4)(n + 1) n = 4, -1
-8. The numbers can be generated by the following quadratic: t(n) = -6n2 + 23n - 4 for n = 1, 2, 3, ...
was this answered becuase i need to know too
The pattern is Un = 6n2 - 7n + 1 = (6n - 1)*(n - 1) where n = 1, 2, 3, ...
8 (again) The sequence is generated by t(n) = (-n3 + 6n2 + 7n - 12)/6 for n = 1, 2, 3, ...