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Out of that list, just 5.

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To be divisible by 2 the last digit must be even, ie one of {0, 2, 4, 6, 8}

The last digit is 5 which is not even (it is odd), so 745 is not divisible by 2

To be divisible by 3 the sum of the digits must also be divisible by 3; if the summing is repeated until a single digit remains, then the original number is only divisible by 3 if this single digit is divisible by 3, ie it is one of {3, 6, 9}

745 → 7 + 4 + 5 = 16

16 + 1 + 6 = 7

7 is not divisible by 3 (it is not one of {3, 6, 9}), so 745 is not divisible by 3

To be divisible by 5, the last digit must be 0 or 5

The last digit of 745 is 5 which is one of {0, 5}, so 745 is divisible by 5

To be divisible by 9 the sum of the digits must also be divisible by 9; if the summing is repeated until a single digit remains, then the original number is only divisible by 9 if this single digit is 9 (otherwise this single digit gives the remainder when the original number is divided by 9)

745 + 7 + 4 + 5 = 16

16 → 1 + 6 = 7

7 is not 9, so 745 is not divisible by 9 (the remainder is 7)

To be divisible by 10 the last digit must be 0

The last digit of 745 is 5 which is not 0, so 745 is not divisible by 10.

745 is not divisible by 2, 3, 9, 10

745 is divisible by 5.

Q: Is 745 divisible by 2 3 5 9 or 10?

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It is divisible by 2 and 3. It isn't divisible by 5 and 10.

9 is divisible by 3 10 is divisible by 2, 5 and 10. Everything else, no.

No since only numbers in which its sum can be divisible by 3 is divisible by 3. 2 + 4 + 4 is 10, and 10 is not divisible by 3.

It is evenly divisible by 2 and by 3.

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Related questions

To determine what number 745 is divisible by, you need to check for divisibility rules of different numbers. 745 is not divisible by 2 because it is not even. It is not divisible by 3 because the sum of its digits (7+4+5 = 16) is not a multiple of 3. It is not divisible by 5 because it does not end in 0 or 5. However, 745 is divisible by 5 because the last digit is 5.

It is divisible by 2 and 3. It isn't divisible by 5 and 10.

It is evenly divisible by 2 and 10 but not by 3 and 9.

Yes, it is divisible by 2, 3 and 9, but is not exactly divisible by 5 or 10.

9 is divisible by 3 10 is divisible by 2, 5 and 10. Everything else, no.

20 is divisible by 2, 5 and 10. It is not exactly divisible by 3 or 9.

It is divisible by 2, 5 and 10, but not 3 and 9.

It is divisible by 2 & 3. It is not divisible by 5, 9 & 10. 534 is even → divisible by 2 5 + 3 + 4 = 12 → divisible by 3 534 does not end in 0 or 5 → not divisible by 5 5 + 3 + 4 = 12 → not divisible by 9 534 does not end in 0 → not divisible by 10

No since only numbers in which its sum can be divisible by 3 is divisible by 3. 2 + 4 + 4 is 10, and 10 is not divisible by 3.

29,178 is divisible by 2, 3 and 9, not by 5 or 10.

It is evenly divisible by 2 and by 3.

Because 410 ends in 0, it is divisble by 10. To determine if it's divisible by 6, it needs to be divisible by 2 and 3. it is divisible by 2, as it is even, but is not divisible by 3;