Yes, 7 is a factor of 63.
The factors of 63 are 1, 3, 7, 9, 21, and 63.
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Because 9*7 = 63 with no remainder
7 x 9 = 63 7 is a FACTOR of 63 9 is a FACTOR of 63 7 and 9 are even DIVISORS of 63 63 is a MULTIPLE of 7 and 9 63 is a PRODUCT of 7 and 9 63 is evenly DIVISIBLE by 7 or 9
63/9 = 7 and 63/7 = 9 So, yes they factors of 63.
The Greatest Common Factor of 28, 42, 63: 7
It is 7 because the product of its prime factors are: 3*3*7 = 63