7 x 9 = 63 7 is a FACTOR of 63 9 is a FACTOR of 63 7 and 9 are even DIVISORS of 63 63 is a MULTIPLE of 7 and 9 63 is a PRODUCT of 7 and 9 63 is evenly DIVISIBLE by 7 or 9
Yes, 7 is a factor of 63. The factors of 63 are 1, 3, 7, 9, 21, and 63.
Because 9*7 = 63 with no remainder
factor OS 63 63 - 1, 3, 7, 9, 21, 63 7 and 9 add up to 16 7+9=16
1, 3, 7, 9, 21, 63 3 and 7 are prime.
7 x 9 = 63 7 is a FACTOR of 63 9 is a FACTOR of 63 7 and 9 are even DIVISORS of 63 63 is a MULTIPLE of 7 and 9 63 is a PRODUCT of 7 and 9 63 is evenly DIVISIBLE by 7 or 9
Yes, 7 is a factor of 63. The factors of 63 are 1, 3, 7, 9, 21, and 63.
63/9 = 7 yes
Because 9*7 = 63 with no remainder
1, 3, 7, 9, 21, 63
1, 3, 7, 9, 21, 63
63 ^ 7*9 ^ 3*3
Anything that isn't 1, 3, 7, 9, 21, 63
7 is a factor of 28 because 4 x 7 equals 28. 7 is a factor of 63 because 9 x 7 = 63. That makes 7 a common factor of 28 and 63. The factors of 28 that are larger than 7 are 14 and 28. The factors of 63 that are larger than 7 are 9, 21 and 63. Since none of those numbers are the same, that makes 7 the greatest common factor of 28 and 63.
1, 3, 7, 9, 21, 63
1, 3, 7, 9, 21, 63.
1, 3, 7, 9, 21, 63.