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Yes.

Every number is divisible by every other number except 0. Therefore the answer is yes.

If you actually meant is 834 evenly divisible by 2, 3, 5, 9 or 10 [with no remainder], then the answer is also yes because 834 is evenly divisible by both 2 and 3. It is not evenly divisible by 5, 9 and 10 but the 'or' in the question implies that it only need be divisible by one or more of the values, not necessarily all of them. If you really meant all of them, then the answer is no.

In short, 834 is evenly divisible by 2 and 3, but not by 5, 9 or 10.

It is obviously evenly divisible by 2 since 834 is an even number: 834 / 2 = 417.

It is obviously evenly divisible by 3 since 834 / 3 is 278.

It is obviously not evenly divisible by 5 since the least-significant digit (4) is neither 5 nor 0.

It is obviously not evenly divisible by 9 because the digits do not recursively add up to 9. That is, 8 + 3 + 4 = 15 => 1 + 5 = 6. Ergo, 6 <> 9 therefore 834 is not evenly divisible by 9.

It is obviously not evenly divisible by 10 since the least-significant digit (4) is not 0.

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Q: Is 834 divisible by 2 3 5 9 or 10?
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