Q: Is 896 divisibility by 5

Write your answer...

Submit

Still have questions?

Continue Learning about Math & Arithmetic

2.50

It really isn't worthwhile to find complicated divisibility rules for large numbers like 305 - because if there really is a divisibility rule, it will certainly be more complicated than just doing the division.Anyway, 305 = 5 x 61, so if a number is divisible by 305, it must be divisible by 5, and by 61. Divisibility by 5 is fairly simple; a number is divisible by 5 if it ends with 0 or 5. For divisibility by 61, see the following link; it looks fairly complicated.http://www.primepuzzles.net/puzzles/puzz_101.htmIt really isn't worthwhile to find complicated divisibility rules for large numbers like 305 - because if there really is a divisibility rule, it will certainly be more complicated than just doing the division.Anyway, 305 = 5 x 61, so if a number is divisible by 305, it must be divisible by 5, and by 61. Divisibility by 5 is fairly simple; a number is divisible by 5 if it ends with 0 or 5. For divisibility by 61, see the following link; it looks fairly complicated.http://www.primepuzzles.net/puzzles/puzz_101.htmIt really isn't worthwhile to find complicated divisibility rules for large numbers like 305 - because if there really is a divisibility rule, it will certainly be more complicated than just doing the division.Anyway, 305 = 5 x 61, so if a number is divisible by 305, it must be divisible by 5, and by 61. Divisibility by 5 is fairly simple; a number is divisible by 5 if it ends with 0 or 5. For divisibility by 61, see the following link; it looks fairly complicated.http://www.primepuzzles.net/puzzles/puzz_101.htmIt really isn't worthwhile to find complicated divisibility rules for large numbers like 305 - because if there really is a divisibility rule, it will certainly be more complicated than just doing the division.Anyway, 305 = 5 x 61, so if a number is divisible by 305, it must be divisible by 5, and by 61. Divisibility by 5 is fairly simple; a number is divisible by 5 if it ends with 0 or 5. For divisibility by 61, see the following link; it looks fairly complicated.http://www.primepuzzles.net/puzzles/puzz_101.htm

if the number ends on 5 or 0 the number is divisible by 5

If the rules for 2 and 3 work, the number is divisibale by 5.

15 divided by 5 is 3 and 15 divided by 3 is 5

Related questions

It is divisibility by 3 and divisibility by 5.Divisibility by 3: the digital root of an integer is obtained by adding together all the digits in the integer, with the process repeated if required. If the final result is 3, 6 or 9, then the integer is divisible by 3.Divisibility by 5: the integer ends in 0 or 5.

2.50

To test divisibility for 20, you need to use the tests for divisibility by 4 and 5.The test for divisibility by 4 is that the last 2 digits of the number, given as a 2-digit number, are divisible by 4.Example for 4:We are testing the number 11042.42/4 = 10.5 which is not a whole number. Therefore 11042 is not divisible by 4.The test for divisibility by 5 is that the last digit of the number is either 5 or 0.

Divisibility is a noun meaning being capable of being divided. Example sentences: "The rule for divisibility by 5 is that the number ends in 0 or 5." "The easy divisibility of the cookies prevented fights among the children." "The divisibility of this pie is questionable, at best."

It really isn't worthwhile to find complicated divisibility rules for large numbers like 305 - because if there really is a divisibility rule, it will certainly be more complicated than just doing the division.Anyway, 305 = 5 x 61, so if a number is divisible by 305, it must be divisible by 5, and by 61. Divisibility by 5 is fairly simple; a number is divisible by 5 if it ends with 0 or 5. For divisibility by 61, see the following link; it looks fairly complicated.http://www.primepuzzles.net/puzzles/puzz_101.htmIt really isn't worthwhile to find complicated divisibility rules for large numbers like 305 - because if there really is a divisibility rule, it will certainly be more complicated than just doing the division.Anyway, 305 = 5 x 61, so if a number is divisible by 305, it must be divisible by 5, and by 61. Divisibility by 5 is fairly simple; a number is divisible by 5 if it ends with 0 or 5. For divisibility by 61, see the following link; it looks fairly complicated.http://www.primepuzzles.net/puzzles/puzz_101.htmIt really isn't worthwhile to find complicated divisibility rules for large numbers like 305 - because if there really is a divisibility rule, it will certainly be more complicated than just doing the division.Anyway, 305 = 5 x 61, so if a number is divisible by 305, it must be divisible by 5, and by 61. Divisibility by 5 is fairly simple; a number is divisible by 5 if it ends with 0 or 5. For divisibility by 61, see the following link; it looks fairly complicated.http://www.primepuzzles.net/puzzles/puzz_101.htmIt really isn't worthwhile to find complicated divisibility rules for large numbers like 305 - because if there really is a divisibility rule, it will certainly be more complicated than just doing the division.Anyway, 305 = 5 x 61, so if a number is divisible by 305, it must be divisible by 5, and by 61. Divisibility by 5 is fairly simple; a number is divisible by 5 if it ends with 0 or 5. For divisibility by 61, see the following link; it looks fairly complicated.http://www.primepuzzles.net/puzzles/puzz_101.htm

896 is only divisible by 2; it is not divisible by 3, 5, 9 nor 10. To be divisible by 2, the number must be even, ie, the last digit must be even, that is one of {0, 2, 4, 6, 8}; 896 ends in 6 which is even, thus 896 is divisible by 2. To be divisible by 3, add the digits of the number together and if the sum is divisible by 3, then so is the original number. The test can be repeated on the sum until a single digit remains; if this single digit is 3, 6, or 9 then the original number is divisible by 3: 896 → 8 + 9 + 6 = 23 → 2 + 3 = 5 which is not one of {3, 6, 9}, thus 896 is not divisible by 3 To be divisible by 5, the last digit must be 0 or 5; 896 ends in 6 which is neither 0 nor 5, so 896 is not divisible by 5. To be divisible by 9, add the digits of the number together and if the sum is divisible by 9, then so is the original number. The test can be repeated on the sum until a single digit remains (which is called the digital root of the number); only if this single digit is 9 will the original number be divisible by 9: 896 → 8 + 9 + 6 = 23 → 2 + 3 = 5 which is not one 9 thus 896 is not divisible by 9; To be divisible by 10 the last digit must be 0; 896 ends if 6 which is not 0, so 896 is not divisible by 10.

89/6 = 14 and 5/6

If the number ends in 5 or 0 the whole number is divisible by 5.

No. to divide by 5, 524 has to have a 5 at the end or a 0 at the end, so no.

if the number ends on 5 or 0 the number is divisible by 5

No.

If the rules for 2 and 3 work, the number is divisibale by 5.