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Q: Is 85743 divisibility by 2 3 5 9 or 10?

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3 and 9. And they divide into 123456789 whether or not you use divisibility rules!

Rule: If it is divisible by 2 and by 3Numbers are divisible by 6 if they are divisible by 3 and 2. Therefore, for example, since 18 is divisible by 3 and 2, it is also divisible by 6.The divisibility rule for 6 is, it can go into the number if 2 and 3 can also.

Divisibility by 48 requires divisibility by 3 AND by 48Divisibility by 3 requires tat the digital root (sum of digits) is divisible by 3.Divisibility by 16 requires that the number formed by the last four digits is divisible by 16.Of both these are satisfied by a number then it is divisible by 48.

The divisibility rule for 42 isdivisibility by 2, ANDdivisibility by 3, ANDdivisibility by 7.Divisibility by 2 requires the number to be even. That means it must end in 0, 2, 4, 6 or 8.Divisibility by 3 requires that the digital root of the number is divisible by 3. That is, the sum of the digits is divisible by 3. If the first sum is large, you can calculate the digital root of the digital root (and again, if necessary) and check that for divisibility by 3.The divisibility rule for 7 is more difficult.Take the last digit (units).From the number formed by the remaining digit, subtract twice the last digit.If the answer is divisible by 7 (including zero or negative numbers), then the original number is divisible by 7.For large numbers, repeat the process to bring the number down to a manageable size.

To check for divisibility by 6 you need to check for divisibility by 2 and by 3. Divisibility by 2: If the number ends with a 0, 2, 4, 6 or 8 it is divisible by 2. If it is not then it is not divisible by 2 and so cannot be divisible by 6. Divisibility by 6: If the digital root is divisible by 3 then the number is divisible by 3. If it is not then it is not divisble by 3 and so cannot be divisible by 6. The digital root is simply the sum of all the digits in the number. And, if the answer has more than 2 digits, you can repeat the process as many times as you like. For example, 7987 7+9+8+7 = 31 3+1 = 4 So the digital root of 7987 is 4. That is not divisible by 3 and so neither is 7987.

Related questions

It is divisible by 3 and 9 but not the others.

144 is divisibility by 2, 3, 6, and 9.

1, 2, 3, 5, 6, 10, 15, 30

the # needs to be divisible by 2 and 3.

the divisibility rule for 2 is: The number is even;the last digit ends with a 2,4,6,8,10, etc.The divisibility rule fir 3 is: The sum of the number is divisible by 3The divisibility rule for 4 is: The last two digits are divisible by 4The divisibility rule for 5 is: The number ends with a 5 or 0The divisibility rule for 6 is: The sum CAN be divisible by 2 and or 3The divisibility rule for 9 is: The sum of the number is divisible by 9The divisibility rule for 10 is : The number ends with a 0

If the number is also divisible by 2 and 3

The divisibility rule for 3 is add up the digits and check for divisibility. 7+2+4 = 13.13 is not evenly divisible by 3 so 724 is not divisibleby 3.

3 and 9. And they divide into 123456789 whether or not you use divisibility rules!

Rule: If it is divisible by 2 and by 3Numbers are divisible by 6 if they are divisible by 3 and 2. Therefore, for example, since 18 is divisible by 3 and 2, it is also divisible by 6.The divisibility rule for 6 is, it can go into the number if 2 and 3 can also.

In number theory, divisibility refers to a numbers "ability" be divided into smaller whole numbers.For instance, 10 is divisible by both 2 and 5. 10/2 gives the whole number 5. But 10 is not divisible by 3, because dividing 10 by 3 would give you a remainder in addition to a whole number (3 in this case).The definition of a prime number uses divisibility in it's formulation: "A prime number p is a number which is not divisible by any number other than 1 and p itself"The divisibility rule is a method that can be used to see if a number is evenly divisible by other numbers. It is a shortcut to determine the number's factors without having to do division.

Test of divisibility by 2:If a number is even then the number can be evenly divided by 2.5890 is an even number so, it is divisible by 2.Test of divisibility by 3:A number is divisible by 3 if the sum of digits of the number is a multiple of 3.Sum of digits = 5+8+9+0 = 22, which is not a multiple of 3.So, 5890 is not divisible by 3.Test of divisibility by 6:In order to check if a number is divisible by 6, we have to check if it is divisible by both 2 and 3 because 6 = 2x3.As we have seen above that 5890 is not divisible by 3 so, 5890 fails to pass the divisibility test by 6.Test of divisibility by 9:If the sum of digits of a number is divisible by 9 then the number is divisible by 9.Sum of digits = 5+8+9+0 = 22, which is not a multiple of 9.So, 5890 is not divisible by 9.Test of divisibility by 5:If the last digit of a number is 0 or 5, then it is divisible by 5.It is clear that 5890 is divisible by 5.Test of divisibility by 10:If the last digit of a number is 0, then the number is divisible by 10.It is clear that 5890 is divisible by 10 as the last digit is 0.

3+7=10

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