3 and 9. And they divide into 123456789 whether or not you use divisibility rules!
To determine if a number is divisible by another number, you need to check if the first number can be divided by the second number without leaving a remainder. For 501105: Divisibility by 2: A number is divisible by 2 if its last digit is even. The last digit of 501105 is 5, which is odd, so 501105 is not divisible by 2. Divisibility by 3: A number is divisible by 3 if the sum of its digits is divisible by 3. The sum of the digits of 501105 is 5+0+1+1+0+5=12, which is divisible by 3, so 501105 is divisible by 3. Divisibility by 5: A number is divisible by 5 if its last digit is 0 or 5. The last digit of 501105 is 5, so 501105 is divisible by 5. Divisibility by 9: A number is divisible by 9 if the sum of its digits is divisible by 9. The sum of the digits of 501105 is 12, which is not divisible by 9, so 501105 is not divisible by 9. Divisibility by 10: A number is divisible by 10 if its last digit is 0. The last digit of 501105 is 5, so 501105 is not divisible by 10.
The divisibility rule for 42 isdivisibility by 2, ANDdivisibility by 3, ANDdivisibility by 7.Divisibility by 2 requires the number to be even. That means it must end in 0, 2, 4, 6 or 8.Divisibility by 3 requires that the digital root of the number is divisible by 3. That is, the sum of the digits is divisible by 3. If the first sum is large, you can calculate the digital root of the digital root (and again, if necessary) and check that for divisibility by 3.The divisibility rule for 7 is more difficult.Take the last digit (units).From the number formed by the remaining digit, subtract twice the last digit.If the answer is divisible by 7 (including zero or negative numbers), then the original number is divisible by 7.For large numbers, repeat the process to bring the number down to a manageable size.
To check for divisibility by 6 you need to check for divisibility by 2 and by 3. Divisibility by 2: If the number ends with a 0, 2, 4, 6 or 8 it is divisible by 2. If it is not then it is not divisible by 2 and so cannot be divisible by 6. Divisibility by 6: If the digital root is divisible by 3 then the number is divisible by 3. If it is not then it is not divisble by 3 and so cannot be divisible by 6. The digital root is simply the sum of all the digits in the number. And, if the answer has more than 2 digits, you can repeat the process as many times as you like. For example, 7987 7+9+8+7 = 31 3+1 = 4 So the digital root of 7987 is 4. That is not divisible by 3 and so neither is 7987.
A number is a multiple of 48 if it's a multiple of 3 and 16 at the same time 48 = 2^4 x 3 = 16 x 3 For example 10032 is a multiple of 48 because 1 + 3 + 2 = 6, which means it's a multiple of 3, and ends in 0032, which means it's a multiple of 16
It is divisible by 3 and 9 but not the others.
the # needs to be divisible by 2 and 3.
Test of divisibility by 2:If a number is even then the number can be evenly divided by 2.5890 is an even number so, it is divisible by 2.Test of divisibility by 3:A number is divisible by 3 if the sum of digits of the number is a multiple of 3.Sum of digits = 5+8+9+0 = 22, which is not a multiple of 3.So, 5890 is not divisible by 3.Test of divisibility by 6:In order to check if a number is divisible by 6, we have to check if it is divisible by both 2 and 3 because 6 = 2x3.As we have seen above that 5890 is not divisible by 3 so, 5890 fails to pass the divisibility test by 6.Test of divisibility by 9:If the sum of digits of a number is divisible by 9 then the number is divisible by 9.Sum of digits = 5+8+9+0 = 22, which is not a multiple of 9.So, 5890 is not divisible by 9.Test of divisibility by 5:If the last digit of a number is 0 or 5, then it is divisible by 5.It is clear that 5890 is divisible by 5.Test of divisibility by 10:If the last digit of a number is 0, then the number is divisible by 10.It is clear that 5890 is divisible by 10 as the last digit is 0.
The divisibility rule for 3 is add up the digits and check for divisibility. 7+2+4 = 13.13 is not evenly divisible by 3 so 724 is not divisibleby 3.
3 and 9. And they divide into 123456789 whether or not you use divisibility rules!
If the number is also divisible by 2 and 3
Yes, you can tell using the divisibility rules. The answers are yes for all but 5 and 10.
5, 10, 15, 20, 25, 30 are the multiples of 5 from 1 to 30.
3+7=10
A number is divisible by 6 if the number is divisible by 2 AND 3.
If the rules for 2 and 3 work, the number is divisibale by 5.
2 : The number ends with a 2, 4, 6, 8, or zero. (The number is 'even'.)3 : The sum of the digits in the number is divisible by 3 .5 : The number ends with a zero or a 5 .6 : The number passes the tests above for both 2 and 3 .10 : The number ends with a zero.