Yes 900 divided by 4 is 225 and 900 divided by 9 is 100
900 is one such number.
9000 / 9 = 1000 9000 / 10 = 900
There are technically infinitely many solutions. But multiply 9 by any whole number, and the product will be evenly divisible by 9. Ex: 9*1 = 9 and 9/9 = 1 9*2 = 18 and 18/9 = 2 9*3 = 27 and 27/9 = 3 ... 9*100 = 900 and 900/9 = 100 You get the idea.
Yes. If a number is divisible by 9 it is also divisible by 3 so "is divisible by 3 and 9" can just say "is divisible by 9". The only numbers that this can be applied to is 9, 90, 900, 9000 and so on. The difference of digits can only be 9 if one of them is 9 and all of the rest of the digits are 0, since there is no digit greater than 9 (in base 10) and 9 minus anything greater than 0 is less than 9.
Multiples of 9 and 6 are also divisible by three, the reverse is not true. 15 is divisible by 3, but not 6 or 9. 27 is divisible by 3 and 9, but not 6. 12 is divisible by 3 and 6, but not 9. 54 is divisible by 3, 6 and 9.
Yes 900 divided by 4 is 225 and 900 divided by 9 is 100
There are many numbers between 500 and 1000 divisible by 3 and 9. Any number divisible by 9 is divisible by 3. How about 900?
900
900
900
900
90, 900, 9000, 90000, etc.
900 is one such number.
9000 / 9 = 1000 9000 / 10 = 900
There are technically infinitely many solutions. But multiply 9 by any whole number, and the product will be evenly divisible by 9. Ex: 9*1 = 9 and 9/9 = 1 9*2 = 18 and 18/9 = 2 9*3 = 27 and 27/9 = 3 ... 9*100 = 900 and 900/9 = 100 You get the idea.
Yes. If a number is divisible by 9 it is also divisible by 3 so "is divisible by 3 and 9" can just say "is divisible by 9". The only numbers that this can be applied to is 9, 90, 900, 9000 and so on. The difference of digits can only be 9 if one of them is 9 and all of the rest of the digits are 0, since there is no digit greater than 9 (in base 10) and 9 minus anything greater than 0 is less than 9.