To determine if 927 is divisible by a number, we need to check if it can be evenly divided by that number without leaving a remainder.
927 is divisible by 3 because the sum of its digits (9 + 2 + 7 = 18) is divisible by 3, which means 927 is also divisible by 3.
However, 927 is not divisible by 2, 5, 9, or 10 because it does not end in 0 or 5 for 2 and 5, and it does not have all the factors of 9 or 10.
1, 3, 9, 103, 309, 927.
Yes.
Yes, both.
No. By definition a prime number is divisible by only two numbers 1 & itself. Since 927 is divisible by at least 1, 3, 309 and 927, it would not be considered a prime. yes
It is divisible by 2 and 3. It isn't divisible by 5 and 10.
Both 927 / 3 = 309 927 / 9 = 103
1, 3, 9, 103, 309, 927.
1, 3, 9, 103, 309, 927
Yes.
Yes, both.
No. By definition a prime number is divisible by only two numbers 1 & itself. Since 927 is divisible by at least 1, 3, 309 and 927, it would not be considered a prime. yes
It is divisible by 2 and 3. It isn't divisible by 5 and 10.
It is evenly divisible by 2 and 10 but not by 3 and 9.
Yes, it is divisible by 2, 3 and 9, but is not exactly divisible by 5 or 10.
9 is divisible by 3 10 is divisible by 2, 5 and 10. Everything else, no.
20 is divisible by 2, 5 and 10. It is not exactly divisible by 3 or 9.
It is divisible by 2, 5 and 10, but not 3 and 9.