Is 927 divisible by 2 3 5 9 10?

Answer 1

To determine if 927 is divisible by a number, we need to check if it can be evenly divided by that number without leaving a remainder.

927 is divisible by 3 because the sum of its digits (9 + 2 + 7 = 18) is divisible by 3, which means 927 is also divisible by 3.

However, 927 is not divisible by 2, 5, 9, or 10 because it does not end in 0 or 5 for 2 and 5, and it does not have all the factors of 9 or 10.

Answer 2

No.