9รท93=
3 and 9. 93 has a digit sum of 12, initially, which is divisible by 3, but not by 9. So 93 is divisible by 3, but not by 9. 99 has a digit sum of 18, initially, which is divisible by 3 and 9. So 99 is divisible by both 3 and 9.
If the sum of the digits can be divided by 3. 93 is divisible by 3 because 9+3=12 we know 12 is divisible by 3 because 1+2=3 so the number is divisible by 3.
No, because 93 divided by 6 is 15.5
NO. 1110 is not divisible by 9. A number is divisible by 9 if the sum of its digits is divisible by 9. 1110 = 1 + 1 + 1 + 0 = 3 (3 is not divisible by 9, thus, 1110 is not divisible by 9.)
9รท93=
Yes and it is 837/9 = 93
3 and 9. 93 has a digit sum of 12, initially, which is divisible by 3, but not by 9. So 93 is divisible by 3, but not by 9. 99 has a digit sum of 18, initially, which is divisible by 3 and 9. So 99 is divisible by both 3 and 9.
93 is divisible by three 31 times.
93 is divisible by 1, 3, 31 and 93 because each of these numbers divide evenly into 93.
Yes, 93 is divisible by 3. If you divide 93 by 3, the quotient is 31.
1, 3, 31, 93
No.
1, 3, 31, 93
If the sum of the digits can be divided by 3. 93 is divisible by 3 because 9+3=12 we know 12 is divisible by 3 because 1+2=3 so the number is divisible by 3.
3 and 31 because 9+3=12 which is 3 because it goes into 12 evenly and 31 because 93 divided by 31 is 3 or 3 times 31 is 93
Yes, 93 / 3 is equal to 31.