To determine if 5894 is divisible by 6, we need to check if it is divisible by both 2 and 3. A number is divisible by 2 if its last digit is even, which is the case for 5894 (4 is even). To check for divisibility by 3, we sum the digits of 5894 (5+8+9+4=26) and check if that sum is divisible by 3, which it is not. Therefore, 5894 is not divisible by 6.
982 x 982 = 964324
982 as a fraction = 982/1
4, 124, 3048 and 1432 are all divisible by 4.
Yes, if x is an integer divisible by 3, then x^2 is also divisible by 3. This is because for any integer x, x^2 will also be divisible by 3 if x is divisible by 3. This can be proven using the property that the square of any integer divisible by 3 will also be divisible by 3.
983 is divisable by three but the resulting answer is not a whole number. 982/3 = 327.333 recurring or 327 and 1/3rd.
No. It would equal 982 1/3
No. To find whether the number is divisible by 3, you add each digits and if it's equal to 9 then it's divisible by 3 because 9 is divisible by 3. 9 + 8 + 2 = 19, 1 + 9 = 10... so it's not divisible by 3.
Yes but it will have a remaider of 2
To determine if 5894 is divisible by 6, we need to check if it is divisible by both 2 and 3. A number is divisible by 2 if its last digit is even, which is the case for 5894 (4 is even). To check for divisibility by 3, we sum the digits of 5894 (5+8+9+4=26) and check if that sum is divisible by 3, which it is not. Therefore, 5894 is not divisible by 6.
982 x 982 = 964324
982 as a fraction = 982/1
No, it is divisible by 3.No, it is divisible by 3.No, it is divisible by 3.No, it is divisible by 3.
4, 124, 3048 and 1432 are all divisible by 4.
It is divisible by 3, for example.It is divisible by 3, for example.It is divisible by 3, for example.It is divisible by 3, for example.
A number is divisible by 3 if the sum of its digits is divisible by 3.
Yes, if x is an integer divisible by 3, then x^2 is also divisible by 3. This is because for any integer x, x^2 will also be divisible by 3 if x is divisible by 3. This can be proven using the property that the square of any integer divisible by 3 will also be divisible by 3.