No
No, the numbers 9, 12, and 15 do not form a Pythagorean triple. A Pythagorean triple consists of three positive integers (a), (b), and (c) such that (a^2 + b^2 = c^2). In this case, if we take 15 as the largest number, (9^2 + 12^2 = 81 + 144 = 225), which equals (15^2). Therefore, 9, 12, and 15 do indeed form a Pythagorean triple.
To determine if 9, 15, and 12 form a Pythagorean triple, we check if the square of the largest number equals the sum of the squares of the other two. Here, 15 is the largest number. Calculating, we have (15^2 = 225) and (9^2 + 12^2 = 81 + 144 = 225). Since both sides are equal, 9, 15, and 12 do form a Pythagorean triple.
45/171 - 9/171 = 36/171
19*9 = 171
0.0526
The Pythagorean thereom is a^2+b^2=c^2. So, you can tell if they are a Pythagorean triple by seeing if the two smaller numbers squared equal the largest number squared. Example. Are 3,4, and 5 a Pythagorean triple? 3^2= 9. 4^2= 16. 5^2= 25. 9+16=25, so they are a triple.
To determine if 9, 15, and 12 form a Pythagorean triple, we check if the square of the largest number equals the sum of the squares of the other two. Here, 15 is the largest number. Calculating, we have (15^2 = 225) and (9^2 + 12^2 = 81 + 144 = 225). Since both sides are equal, 9, 15, and 12 do form a Pythagorean triple.
15, since 15*2 = 9*2 + 12*2
Indeed they do, it is a Pythagorean Triple: 6*6 + 8*8 = 10*10. (62 + 82 = 102, 36 + 68 = 100, 100 = 100) The "basic" Pythagorean Triple of a 3, 4, 5 triangle works out like this: 32 + 42 = 52 9 + 16 = 25 25 = 25 Your triangle, the 6, 8, 10, figure, is a "doubling" of the cited "basic" triple, and any multiple of a Pythagorean Triple will also be another Pythagorean Triple, and a right triangle.
171. (9 x 20 = 180 - 9 = 171).19 x 9 = 171
45/171 - 9/171 = 36/171
-171/9 = -19
Yes. 171/9 = 19
52 - 42 = 25 - 16 = 9 = 32. 3, 4, 5 is a well known Pythagorean triple.
The positive integer factors of 171 are: 1, 3, 9, 19, 57, 171
9 x 19 = 171
171 ÷ 9 = 19