To get 5 using the numbers 19, 2, 6, and 3, you can subtract 6 from 19 to get 13, then subtract 3 from 13 to get 10, and finally subtract 2 from 10 to get 8. So, you cannot get 5 using these specific numbers.
OK, SO 24 - 5 is 19, but how you get there is you count down so 24, 23, 22, 21, 20, 19. You can also do it by setting up a problem:24- 5____OK,SO You can't subtract 5 from 4 and get a positive number, you would get -1. So you borrow. Subtract 1 from the 2 in the tens place and bring that ten to the 4 temporarily to get 14. Then subtract 5 from 14, so 13, 12, 11, 10, 9 and put a 9 under than column. Then, subtract that one from 2 that you took, and your answer is 19! Hope this helps!
5/9-1/3 is the same as 5/9-3/9. This would then subtract out to be 2/9. (2 over 9)
Assuming you include the endpoints (9 and 19, in this case), the calculation you must do is:19 - 9 + 1 If you don't subtract the endpoints (the question would be phrased something like "... between 9 and 19"), you have to subtract one instead of adding one, at the end.
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To get 5 using the numbers 19, 2, 6, and 3, you can subtract 6 from 19 to get 13, then subtract 3 from 13 to get 10, and finally subtract 2 from 10 to get 8. So, you cannot get 5 using these specific numbers.
OK, SO 24 - 5 is 19, but how you get there is you count down so 24, 23, 22, 21, 20, 19. You can also do it by setting up a problem:24- 5____OK,SO You can't subtract 5 from 4 and get a positive number, you would get -1. So you borrow. Subtract 1 from the 2 in the tens place and bring that ten to the 4 temporarily to get 14. Then subtract 5 from 14, so 13, 12, 11, 10, 9 and put a 9 under than column. Then, subtract that one from 2 that you took, and your answer is 19! Hope this helps!
5+5 equals 10 and there are 9 pokemon so subtract 1 and then there are 8 pokemon so subtract 1
5/9-1/3 is the same as 5/9-3/9. This would then subtract out to be 2/9. (2 over 9)
Assuming you include the endpoints (9 and 19, in this case), the calculation you must do is:19 - 9 + 1 If you don't subtract the endpoints (the question would be phrased something like "... between 9 and 19"), you have to subtract one instead of adding one, at the end.
27,26,37... 2+7=9, 9-4=5, 5+8=13, 13-3=10, 10+9=19, 19-2=17, 17+10=27,27-1=26, 26+11=37,37-0=37 add 1 more to first # subtract 1 less to second #
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The next numbers are 27 and 26 and 37.The sequence is:2 to 9 = add 79 to 5 = subtract 45 to 13 = add 813 to 10 = subtract 310 to 19 = add 919 to 17 = subtract 2So the next 3 steps are:add 10 = 27subtract 1 = 26add 11 = 37
5 7/12 - 3 5/6 = 4 19/12 - 3 10/12 = 1 9/12 = 1 3/4
2.11111.... ( Recurring to infinity Let P = 2.1111.... & 10P = 21.1111.... Subtract 9P = 19 ( NB The repeating decimals subtract to zero) P = 19/9 P = 2 1/9 Done!!!!!
This is a two-phase sequence. Add a number - start with 7 and increase by 1 at each addition. Subtract a number - start with 4 and decrease by 1 at each subtraction. 2 + 7 = 9 ................9 - 4 = 5 5 + 8 = 13 ...............13 - 3 = 10 10 + 9 = 19 ...............19 - 2 = 17 17 + 10 = 27 ...............27 - 1 = 26
Just subtract 9.