be2 is paramagnetic
Yes, Be2-1 exists in the gas phase.
B2 is paramagnetic due to the presence of unpaired electrons in its molecular orbital configuration. In B2, the molecular orbitals are filled as follows: σ(1s)², σ(1s)², σ(2s)², σ(2s)², and then σ(2p)², π(2p)², leading to two unpaired electrons in the π(2p) orbitals. In contrast, C2 has all its electrons paired, resulting in a completely filled set of molecular orbitals: σ(1s)², σ(1s)², σ(2s)², σ(2s)², σ(2p)², and π(2p)². Thus, C2 is diamagnetic because it lacks unpaired electrons.
it is paramagnetic (go to wikipedia for more info)
If you include 8 and 171, there would be 171-8+1 = 164 If you dont include both, it would be2 less -> 162
No, just very weakly ferromagnetic. Unless your paperclip is made out of NH4[Fe(SO4)2]·12H2O.
Diamagnetic
It is paramagnetic because it has unpaired electrons.
diamagnetic
Calcium is diamagnetic.
Tungsten is diamagnetic.
B2 is paramagnetic.
Vanadium is paramagnetic.
Vanadium (V3) is paramagnetic.
No, argon is not paramagnetic. Paramagnetic materials have unpaired electrons, which argon does not have. Argon is a noble gas with a full electron shell, making it diamagnetic.
Sodium is diamagnetic, which means it has no unpaired electrons and is weakly repelled by a magnetic field.
Diamagnetic. All of the electrons are paired.
Paramagnetic molecules have unpaired electrons, while diamagnetic molecules have all paired electrons. One can determine if a molecule is paramagnetic or diamagnetic by examining its electron configuration and counting the number of unpaired electrons. If there are unpaired electrons, the molecule is paramagnetic; if all electrons are paired, the molecule is diamagnetic.