Product of a prime number and a composite number results in a composite number.Now consider the product of a composite number(a) and a prime number(b) is equal to c.i.e. c = a x bIt is clear that c is divisible by both a and b.Also c is divisible by itself and 1, this means that c has more than two factors.A number having more than two factors is composite, therefore product of a prime number and a composite number results in a composite number.
yes b/c 1 is neither prime or composite
None.A composite number c must have a prime factor psuch that 1 < p < c.Therefore the product of c's factors must be at least p*c which must be greater than c.
If you mean 'prime' factors, then an odd number of them CAN'T produce a perfect square. Consider 3 factors ... A, B, and C. If their product were a perfect square, then AxB=C, which can't be true if C is a prime number. For non-prime factors, an odd number of them may or may not be a perfect square: Three factors = not a square: 2 x 3 x 5 = 30. Three factors = a square: 2 x 3 x 6 = 36.
Assuming that a and c are both integers, 10ac must be composite because it is equal to 2*5*a*c.
Product of a prime number and a composite number results in a composite number.Now consider the product of a composite number(a) and a prime number(b) is equal to c.i.e. c = a x bIt is clear that c is divisible by both a and b.Also c is divisible by itself and 1, this means that c has more than two factors.A number having more than two factors is composite, therefore product of a prime number and a composite number results in a composite number.
3, 61 and 113 are prime; the rest composite.
yes b/c 1 is neither prime or composite
None.A composite number c must have a prime factor psuch that 1 < p < c.Therefore the product of c's factors must be at least p*c which must be greater than c.
Any number of the form n = a*b*c*d*e*f where a, b, c, d, e and f are different prime numbers. n has 26 = 64 factors in total, of which 1 is the number 1 (neither prime nor composite), 6 are prime, and the remaining 57 are composite.
C+1 if C is not composite, and C+2 if C is a composite.
If you mean 'prime' factors, then an odd number of them CAN'T produce a perfect square. Consider 3 factors ... A, B, and C. If their product were a perfect square, then AxB=C, which can't be true if C is a prime number. For non-prime factors, an odd number of them may or may not be a perfect square: Three factors = not a square: 2 x 3 x 5 = 30. Three factors = a square: 2 x 3 x 6 = 36.
Assuming that a and c are both integers, 10ac must be composite because it is equal to 2*5*a*c.
#include<iostream.h> #include<conio.h> int main() { int i,n; clrscr(); cout<<"PROGRAM TO CHECK IF THE NUMBER IS PRIME OR NOT:"<<endl; cout<<"Enter a number:"; cin>>n; for(int i=2;i<n;i++) { if(n%i==0) cout<<"\nTHE NUMBER IS COMPOSITE"<<endl; else cout<<"\nTHE NUMBER IS PRIME"<<endl; } return 0; }
The letter that represent the composite number is letter C.
It's even. All even numbers (except for 2) are composite.
Your options C and D are the same, but it is true that 51 is a composite number.