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1295.085 x 10 14 write in scientific notation?
1,295.085 x 1014
What time 39 equals 1014?
1014 / 39 = 26
Is the value of Kw always 1.0 x 10-14?
yes.
What is 2998 x 108 divided by 510 x 1014?
Rounded to three decimal places, (2998 x 108) / (510 x 1014) = 0.626
WHAT IS 8.1 TIMES 1014 plus 1.5 X 1015?
810000000000000 + 1500000000000000 = 2310000000000000 = 2.31 x 10^15
Is 1014 equal?
1,014 = 1 x 1014, 2 x 507, 3 x 338, 6 x 169, 13 x 78, 26 x 39. It is an even number.
What is the pH of pure water at 313 K if Kw at that temperature is 2.917 x 10 -14?
Kw = [H+][OH-] [H+] = 10-pH = 10-6.17 For [OH-] remember that heat causes more water molecules to self-dissociate but for every new H+ generated, a OH- is generated as well. Therefore, the concentration of H+ and OH- is equal. [OH-] = 10-6.17 Kw = [H+][OH-] = 10-6.17 * 10-6.17 = 10-12.34
One light year is 5.88 x 1014 miles so if star 5A is 5.417 x 1014 miles from planet X how many light years is it from Planet x to star 5A?
Star 5A is 5.417 x 10^14 miles away from planet X. To convert this to light years, divide this distance by 5.88 x 10^14 miles per light year. This gives a distance of approximately 0.92 light years from planet X to star 5A.
1295.085 x 10 14 write in scientific notation?
1,295.085 x 1014
What is 7.5 X 10 to the 14th power?
Expressed numerically, 7.5 x 1014 = 750000000000000
An acid has Ka equals 2.5 x 10-4 what is the Kb for the conjugate base of this acid at 25C Kw equals 1.0 x 10-14 at 25C?
To find the Kb of the conjugate base, use the relationship Kw = Ka x Kb. Rearrange the equation for Kb: Kb = Kw / Ka = (1.0 x 10^-14) / (2.5 x 10^-4) = 4.0 x 10^-11.
At a certain temperature the pH of a neutral solution is 7.56 What is the value of Kw at that temperature?
Kw = [H+][OH-][H+] = 10-pH = 10-7.56In neutral pure water the concentration of H+ and OH- is equal.[OH-] = 10-7.56Kw = [H+][OH-] = 10-7.56 * 10-7.56 = 10-15.12
What is the numerical value of Kw at 298 k?
The value of Kw (ion product of water) at 298 K is approximately 1.00 x 10^-14.
An acid has Ka equals 3.1 x 10-10 What is the Kb for the conjugate base of this acid at 25 C?
To find the Kb of the conjugate base, you can use the relationship Kw = Ka * Kb. At 25°C, the value of Kw is 1.0 x 10^-14. Given Ka = 3.1 x 10^-10, you can solve for Kb using Kb = Kw / Ka. This gives you Kb = 1.0 x 10^-14 / 3.1 x 10^-10 = 3.23 x 10^-5.
How do you write standard a form correct to 2 significant figures?
(4.6 x 10)-7 x (7.2 x 1014)
How many nanometers does 782.0 km equal?
782 km = 7.82 x 1014 nanometers = 782,000,000,000,000 nm
What time 39 equals 1014?
1014 / 39 = 26
