Efficiency = Output value / Input valueFor example, if a machine needs 10 KW to run and produces 8 KW, its power efficiency is 8/10 = 0.8 or 80%Efficiency is always between 0 and 1 (or 0 and 100 if expressed as a percentage.)
No. Kw is a measure of power with units [ML2T-3] whereas 1.0*10-14 is a pure, dimensionless number. There can be no equivalence because the dimensions do not match.
50 W * (1 kW/1000 W) * (10 hr/day) = 0.5 kW-hr/dayAssuming 30 days/mo.--> 0.5 kw-hr/day*(30 day/month) = 15 kW-hr/month
10
1 Megawatt = 1000 Kilowatts so 30 Mw = 30*1000 kw = 30,000 kw.
The value of Kw (ion product of water) at 298 K is approximately 1.00 x 10^-14.
Kw = [H+][OH-][H+] = 10-pH = 10-7.56In neutral pure water the concentration of H+ and OH- is equal.[OH-] = 10-7.56Kw = [H+][OH-] = 10-7.56 * 10-7.56 = 10-15.12
Kw = [H+][OH-] [H+] = 10-pH = 10-6.17 For [OH-] remember that heat causes more water molecules to self-dissociate but for every new H+ generated, a OH- is generated as well. Therefore, the concentration of H+ and OH- is equal. [OH-] = 10-6.17 Kw = [H+][OH-] = 10-6.17 * 10-6.17 = 10-12.34
Efficiency = Output value / Input valueFor example, if a machine needs 10 KW to run and produces 8 KW, its power efficiency is 8/10 = 0.8 or 80%Efficiency is always between 0 and 1 (or 0 and 100 if expressed as a percentage.)
The ionization constant Kw for water at 25 degrees Celsius is 1.0 x 10^-14.
Power Factor = KVA/KW. This has no unit. Its value is always 1 or less.
Kw is the ionisation constant for water at 25°C which value is 1.0x10^-14. (chemistry)In water at any pH the equilibrium state Kw is defined by and equal to the 'ion product':Kw = [H3O+]*[OH-] = 1.0*10-14at room temperature 25°C
1 MW is 1000 kW therefore 10 MW is equal to 10,000 kW.
The value of Kw, which is the equilibrium constant for the autoionization of water, can be changed by changing the temperature of the water. As temperature increases, the value of Kw also increases because the ionization of water is an endothermic process.
import math def ph_to_ppm(ph): """Converts a pH value to ppm. Args: ph: The pH value to convert. Returns: The pH value in ppm. """ kw = 10 ** -ph t = 25 + 273.15 ion_product = kw * math.pow(10, -(t / 12.0)) return 10 ** (-ion_product / 2) if __name__ == "main": print(ph_to_ppm(7.4))
To find the Kb of the conjugate base, you can use the relationship Kw = Ka * Kb. At 25°C, the value of Kw is 1.0 x 10^-14. Given Ka = 3.1 x 10^-10, you can solve for Kb using Kb = Kw / Ka. This gives you Kb = 1.0 x 10^-14 / 3.1 x 10^-10 = 3.23 x 10^-5.
Kw value of water is 1.0*10-14 moles2/L2 at room temperature. So the H3O+ ion concentration is 10-7 moles/L.