Efficiency = Output value / Input valueFor example, if a machine needs 10 KW to run and produces 8 KW, its power efficiency is 8/10 = 0.8 or 80%Efficiency is always between 0 and 1 (or 0 and 100 if expressed as a percentage.)
No. Kw is a measure of power with units [ML2T-3] whereas 1.0*10-14 is a pure, dimensionless number. There can be no equivalence because the dimensions do not match.
50 W * (1 kW/1000 W) * (10 hr/day) = 0.5 kW-hr/dayAssuming 30 days/mo.--> 0.5 kw-hr/day*(30 day/month) = 15 kW-hr/month
10
1 Megawatt = 1000 Kilowatts so 30 Mw = 30*1000 kw = 30,000 kw.
The value of Kw (ion product of water) at 298 K is approximately 1.00 x 10^-14.
Kw = [H+][OH-][H+] = 10-pH = 10-7.56In neutral pure water the concentration of H+ and OH- is equal.[OH-] = 10-7.56Kw = [H+][OH-] = 10-7.56 * 10-7.56 = 10-15.12
Kw = [H+][OH-] [H+] = 10-pH = 10-6.17 For [OH-] remember that heat causes more water molecules to self-dissociate but for every new H+ generated, a OH- is generated as well. Therefore, the concentration of H+ and OH- is equal. [OH-] = 10-6.17 Kw = [H+][OH-] = 10-6.17 * 10-6.17 = 10-12.34
Efficiency = Output value / Input valueFor example, if a machine needs 10 KW to run and produces 8 KW, its power efficiency is 8/10 = 0.8 or 80%Efficiency is always between 0 and 1 (or 0 and 100 if expressed as a percentage.)
The ionization constant Kw for water at 25 degrees Celsius is 1.0 x 10^-14.
Power Factor = KVA/KW. This has no unit. Its value is always 1 or less.
Kw is the ionisation constant for water at 25°C which value is 1.0x10^-14. (chemistry)In water at any pH the equilibrium state Kw is defined by and equal to the 'ion product':Kw = [H3O+]*[OH-] = 1.0*10-14at room temperature 25°C
1 MW is 1000 kW therefore 10 MW is equal to 10,000 kW.
import math def ph_to_ppm(ph): """Converts a pH value to ppm. Args: ph: The pH value to convert. Returns: The pH value in ppm. """ kw = 10 ** -ph t = 25 + 273.15 ion_product = kw * math.pow(10, -(t / 12.0)) return 10 ** (-ion_product / 2) if __name__ == "main": print(ph_to_ppm(7.4))
To find the Kb of the conjugate base, you can use the relationship Kw = Ka * Kb. At 25°C, the value of Kw is 1.0 x 10^-14. Given Ka = 3.1 x 10^-10, you can solve for Kb using Kb = Kw / Ka. This gives you Kb = 1.0 x 10^-14 / 3.1 x 10^-10 = 3.23 x 10^-5.
Kw value of water is 1.0*10-14 moles2/L2 at room temperature. So the H3O+ ion concentration is 10-7 moles/L.
A hydronium ion concentration of 10^-7 M in water indicates a neutral pH of 7, as it corresponds to a balanced concentration of hydronium and hydroxide ions. At this concentration, there are equal amounts of H3O+ and OH- ions present, resulting in a neutral solution.