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What is the cars acceleration if it accelerates uniformly from rest to 24 ms south in 18 s?
24 (m/s) / 18 s = 1.33 m/s/s or 1.33 m/s224 (m/s) / 18 s = 1.33 m/s/s or 1.33 m/s224 (m/s) / 18 s = 1.33 m/s/s or 1.33 m/s224 (m/s) / 18 s = 1.33 m/s/s or 1.33 m/s2
What is your acceleration if you travel 50 meters in 30 seconds at a constant speed?
Meed velocity first. V = delta X/delta t V = 50 m/30 s = 1.666 m/s now, acceleration A = delta V/delta t A = 1.666 m/s/30 s = 0.056 m/s2 ============
How do you calculate the acceleration if stationary car that accelerates to 20meterper second travelling in 5 seconds?
Remember the equation for acceleration. a = (v - u ) / t Were a = acce;leration v = final speed ( 20 m/s) u = initial speed ( 0 m/s) t = time ( 5 s) Substituting a = ( 20 m/s - 0 m/s) / 5s a = 20m/s / 5s a = 4 m /s^2
Why do units of acceleration have two time units?
Acceleration = (v - u)/t Replace each variable in the equation with their units Acceleration = (m/s - m/s) / s Same common denominator (m - m/s)/s Apply divison of fractions (m-m)/s*s (m/s^2) Note: I know m - m = 0 but they are just units expressing metres!
When the bus decelerates uniformly at 5 point 3 m per s2 it slows from 8.5 m per s to 0 m per s what is the time interval of acceleration for the bus?
Vf = V0 + at --> 0 = (8.5 m/s) - (5.3 m/s²)t -> t = (8.5 m/s)/(5.3 m/s²) = 1.60377 s
