YES!!!
10^(2) X 10^(4) =
10^(2 + 4) =
10^(6)
Rules for indices,
#1 ; the coefficient MUST be the same in both numbers.
#2 ; for multiplication you ADD the indices
#3 ; for division you subtract the indices
#4 ; for 'nesting' you multiply the indices.,
Using your figures '-
#1 is satisfied as the coefficient is the same , at '10', in both terms.
#2 as per the question multiplication 10^(2) X 10^(4) = 10^(2+4) = 10^(6)
#3 If dividing 10^(2) / 10^(4) = 10^(2 - 4) = 10^(-2) - 1/10^(2) = 1/100
#4 if 'nesting' (10^(2))^(4) = 10^(2 x 4) = 10^(8) = 100,000,000
Similarly 2^(3) X 2^( 6) = 2^(3 + 6) = 2^(9)
However, 2^(3) X 3^(2) cannot be done as the coefficients are different.
simplified it would equal: 24x to the third power - x to the second power - x to the sixth power - 34
Yes, (4/12) and (6/18) are equal.
a math question
60
1,000,000
24u to the second power. Differentiate 40u to the fifth power which is 200u to the fourth power and 5u to the second power which is 10u. Subtract 400u to the sixth power from 1000u to the sixth power which is 600u to the sixth power. Then square 5u to the second power which is 25u to the fourth power. Finally, divide 600u to the sixth power by 25u to the fourth power. The solution is 24u to the second power. Another method is simplifying it to 8u cubed (to the third power) and taking the power rule. Take 3 times 8u which is 24u and subtract 1 from 3 in exponent which is 2. The answer is 24u to the second power.
1/4 to the sixth power (0.256) equals 0.0002
simplified it would equal: 24x to the third power - x to the second power - x to the sixth power - 34
6^4 = 1,296
the answer my friend is blowing in the wind
Yes, (4/12) and (6/18) are equal.
a math question
Second, third, fourth, fifth, sixth and so on.
fourth term of X-Y to the sixth power
first: Hashirama Sejnu second: Tobirama Senju third: Hiruzen Sarutobi fourth: Minato Namikaze fitht: Tsunade sixth: Danzou
15625
60