11 x 47, or 517 x 1
I guess you want the area of the rectangle 517 cm wide by 900 cm long: area = 517 cm x 900 cm = 465300 cm2
8 with 517 remaining 6,973 - 517 = 6,456 = 807 x 8
517 - without using a calculator !
I tried to find f by integrating the partial derivatives, but since 1/r is multiplying the whole vector, I just took it out, I'm not sure if I can do that. Like this: ∂f∂x(x,y,z)=x ∂f∂y(x,y,z)=y ∂f∂z(x,y,z)=z thus f(x,y,z)=x22+g(y,z) f(x,y,z)=y22+h(x,z) f(x,y,z)=z22+k(x,y) for some functions g, h, and k, so if g=y22+z22, h=x22+z22 and k=x22+y22, the function f is: f(x,y,z)=1r(x22+y22+z22)=12r⋅r2=r2 Am I correct? If not, how can I solve this correctly, should I integrate x/r, y/r and z/r instead?
there is x18 x19 and x22 they are like sport bikes but smaller the x22 is 27in seat height
11 x 47, or 517 x 1
530
1227.
I guess you want the area of the rectangle 517 cm wide by 900 cm long: area = 517 cm x 900 cm = 465300 cm2
8 with 517 remaining 6,973 - 517 = 6,456 = 807 x 8
16 ft x 22 ft = 352 ft2
22 x 22 = By Long Multiplication 22 x22 440 44 =484 =====
6.8/65.38=0.104mol 0.104 x 6.022 x 10^23=6.263^10 x22
517 - without using a calculator !
I tried to find f by integrating the partial derivatives, but since 1/r is multiplying the whole vector, I just took it out, I'm not sure if I can do that. Like this: ∂f∂x(x,y,z)=x ∂f∂y(x,y,z)=y ∂f∂z(x,y,z)=z thus f(x,y,z)=x22+g(y,z) f(x,y,z)=y22+h(x,z) f(x,y,z)=z22+k(x,y) for some functions g, h, and k, so if g=y22+z22, h=x22+z22 and k=x22+y22, the function f is: f(x,y,z)=1r(x22+y22+z22)=12r⋅r2=r2 Am I correct? If not, how can I solve this correctly, should I integrate x/r, y/r and z/r instead?
7/10 + 5/17 = 169/170