11 = 4/.4 +4/4 13 =( 4! radical( 4) + 4 )/4 13 = 4/,4/ + radical(4) + radical(4)
4√5 + 4√5 = 8√5.
4 radical 6
The expression "the radical of 4 times the radical of 7" can be written mathematically as (\sqrt{4} \times \sqrt{7}). Since (\sqrt{4} = 2), the expression simplifies to (2 \times \sqrt{7}). Thus, the final answer is (2\sqrt{7}).
If we read this carefully, what you're asking for is (4 of something) minus (1 of the same thing). The result is 3 of them . . . 3 radical 6.
radical(48)/radical(3) = radical(48/3) = radical(16) = 4 Technically, radical(16) is +4 OR -4 but in such questions often only the principal root is required.
4 radical 3 is about 6.92820323
11 = 4/.4 +4/4 13 =( 4! radical( 4) + 4 )/4 13 = 4/,4/ + radical(4) + radical(4)
4√5 + 4√5 = 8√5.
4 radical 6
First, note that radical 4 is 2. So 3xradical 4 is just 6, Now we have 6+2 radical 3. You can't do much with this except factor out a 2 if you want 2(3+Radical 3)
To simplify the expression radical 6 minus 4 radical 6, we first combine like terms. Since both terms have the same radical part (radical 6), we can subtract the coefficients in front of the radicals. This gives us -3 radical 6 as the simplified answer.
4 times radical 34
2 radical(8) = 4 radical(2)
Silicate radical is( SiO4) and its valency is -4
The expression "the radical of 4 times the radical of 7" can be written mathematically as (\sqrt{4} \times \sqrt{7}). Since (\sqrt{4} = 2), the expression simplifies to (2 \times \sqrt{7}). Thus, the final answer is (2\sqrt{7}).
If we read this carefully, what you're asking for is (4 of something) minus (1 of the same thing). The result is 3 of them . . . 3 radical 6.