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What is x2-3x-1 equals 0?
x^2 - 3x - 1 = 0 x = -b+-root(b^2 - 4ac)/2a x = 3 +-root(9+4)/2 Two solutions: 1. x = (3+root(13))/2 2. x = (3-root(13))/2
What number is its own square root?
The square root of 1 is 1.The square root of 0 is 0.
What is the value of x in x squared - 2x - 1 equals 0 please show working outs?
This is a quadratic equation in the form of x2-2x-1 = 0 which will have two solutions and can be solved using the quadratic equation formula: x = -b/2a + and - the square root of (b2-4ac)/2a Whereas in this equation a = 1, b = -2 and c = -1 Solutions: x = 1-the square root of 2 or x = 1+the square root of 2 Remember that (- -2) = 2, (-2)2 = 4 and (-4*1*-1) = 4
When are these kinds of numbers solutions to quadratic equations?
You need to be more specific. A quadratic equation will have 2 solutions. The 2 solutions can be equal (such as x² + 2x + 1 = 0, solution is -1 and -1). If one of the solutions is a real number, then the other solution will also be a real number. If one of the solutions is a complex number, then the other solution will also be a complex number. [a complex number has a real component and an imaginary component]In the equation: Ax² + Bx + C = 0. The term [B² - 4AC] will determine if the solution is a double-root, or if the answer is real or complex.if B² = 4AC, then a double-root (real).if B² > 4AC, then 2 real rootsif B² < 4AC, then the quadratic formula will produce a square root of a negative number, and the solution will be 2 complex numbers.If B = 0, then the numbers will be either pure imaginary or real, and negatives of each other [ example 2i and -2i are solutions to x² + 4 = 0]Example of 2 real and opposite sign: x² - 4 = 0; 2 and -2 are solutions.
What are the solutions to the equation x2 plus 3x plus 3 equals 0?
x2 + 3x + 3 = 0 doesn't factor neatly. Applying the quadratic formula we find two imaginary solutions: (-3 plus or minus the square root of -3) divided by 2x = -1.5 + 0.8660254037844386ix = -1.5 - 0.8660254037844386iwhere i is the square root of negative 1
