x2 + 3x + 3 = 0 doesn't factor neatly. Applying the quadratic formula we find two imaginary solutions: (-3 plus or minus the square root of -3) divided by 2
x = -1.5 + 0.8660254037844386i
x = -1.5 - 0.8660254037844386i
where i is the square root of negative 1
One.
one
In the equation 3x plus 7 equals 13, x is equal to 2.
It is a simultaneous equation and when solved its solutions are x = 71/26 and y = 50/13
The equation (3x + 8 = 3x - 5) has no solutions because when we attempt to isolate (x), we end up with a contradiction. Subtracting (3x) from both sides results in (8 = -5), which is not true. Since there are no values of (x) that can satisfy this equation, it has no solutions.
One.
one
There are no real solutions because the discriminant of the quadratic equation is less than zero.
If: 3x+2y = 5x+2y = 14 Then: 3x+2y = 14 and 5x+2y =14 Subtract the 1st equation from the 2nd equation: 2x = 0 Therefore by substitution the solutions are: x = 0 and y = 7
x = 5 or x = 6
is an equation of a line in plane coordinate geometry. The coordinates of every point on that line satisfy the equation so there are an infinite number of solutions to the equation.
undefined.
3x + 2y = 8 This is an equation. It could be the equation of a line.
50, 53, 59
In the equation 3x plus 7 equals 13, x is equal to 2.
It is a simultaneous equation and when solved its solutions are x = 71/26 and y = 50/13
x^2 + 3x + 3 = 7 x^2 + 3x - 4 = 0 (x - 1)(x + 4) = 0 x = 1 or x = -4