Yes, you see as Velocity = Displacement/Time, To get displacement by its self, we need to get the 1/time over to the other side. The only way to do this is to multiply both sides by Time/1 to cancel out time on the Displacement/Time side and to make it so Velocity is multiplied by time. So Time/1 x Velocity = Displacement/Time x Time/1. The time and the time on the right side of the equation cancel out to become onem and the new equation is Time x Velocity = Displacement. Try it on paper if it becomes to confusing reading my type. Hope this helps!
Velocity is displacement divided by time. Displacement is different from distance traveled, as displacement states how far you traveled in RELATION to a starting point. The formula for Velocity is ---- v = x / t v = Velocity x = Displacement t = Time velocity is a vector quantity so the direction should also be specified unless it is implicit in the problem. ----
Speed is a scaler quantity i.e. it has magnitude only without direction. It can be calculated using the formula : speed = distance/time where distance is the total distance travelled from initial position to final position; time is the total time taken to cover this distance. Velocity is a vector quantity i.e. it has magnitude as well as direction. It can be calculated using the formula : velocity = displacement/time displacement is the distance between final position & initial position; time is the total time taken to cover this displacement. for example: if a body starts from some initial point goes to a certain distance x and returns back to the initial position. So the total distance covered is 2x but displacement is 0 (zero) because initial & final position are same. So its speed is 2x/time while velocity is 0/t = 0(zero)
v = dx/dt (the derivative of 'x' with respect to 't') where 'x' is the displacement of the objectin a given direction, and 't' is time.
Work is not defined as distance/time, but rather: work= force x distance Distance divided by time will give you velocity. Displacement (or distance traveled) = velocity x time
the formula that ties displacement (you can think of it as distance in a given direction), velocity, time and acceleration (a) is : s = s0+vt + 1/2at^2 s0 = initial displacement (you can equate to 0, if you start at 0) vt = starting velocity times time (you can equate to 0 if initial velocity is 0) s= final displacement so s=1/2at^2 = (1/2 x a x t x t), so here you end up with a relationship between displacement, acceleration and time. (note: ^2 stands for "to the 2nd power")
Velocity is displacement divided by time. Displacement is different from distance traveled, as displacement states how far you traveled in RELATION to a starting point. The formula for Velocity is ---- v = x / t v = Velocity x = Displacement t = Time velocity is a vector quantity so the direction should also be specified unless it is implicit in the problem. ----
v=dx/dt, where v= velocity x=displacement t=time
acceration = velocity X time
The formula for average velocity is: Final velocity + Initial velocity.... then divide by 2 [ (Vf + Vi) / 2 ]. Your answer should be in your measurement of length divided by seconds [ex. m/s]
Distance travelled (displacement). Distance = velocity/time, so velocity * time = distance. Likewise, x = dv/dt so the integral of velocity with respect to time (area under the graph) is x, the distance travelled.
Speed is a scaler quantity i.e. it has magnitude only without direction. It can be calculated using the formula : speed = distance/time where distance is the total distance travelled from initial position to final position; time is the total time taken to cover this distance. Velocity is a vector quantity i.e. it has magnitude as well as direction. It can be calculated using the formula : velocity = displacement/time displacement is the distance between final position & initial position; time is the total time taken to cover this displacement. for example: if a body starts from some initial point goes to a certain distance x and returns back to the initial position. So the total distance covered is 2x but displacement is 0 (zero) because initial & final position are same. So its speed is 2x/time while velocity is 0/t = 0(zero)
If you are talking about a position vs time graph, the slope gives the average velocity. Velocity is displacement/change in time. (Change in position is displacement). Position is on the y axis and time is on the x axis. The slope = (y2-y1)/(x2-x1) = change in position/change in time = average velocity.
velocity = frequency x wavelength
you can't....it's merely impossible! Assuming it is a graph of velocity vs time, it's not impossible, it's simple. Average velocity is total distance divided by total time. The total time is the difference between finish and start times, and the distance is the area under the graph between the graph and the time axis.
v = dx/dt (the derivative of 'x' with respect to 't') where 'x' is the displacement of the objectin a given direction, and 't' is time.
Work is not defined as distance/time, but rather: work= force x distance Distance divided by time will give you velocity. Displacement (or distance traveled) = velocity x time
The average speed of an object is defined as the distance traveled divided by the time elapsed. Velocity is a vector quantity, and average velocity can be defined as the displacement divided by the time. For the special case of straight line motion in the x direction, the average velocity takes the form: