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Yes, you see as Velocity = Displacement/Time, To get displacement by its self, we need to get the 1/time over to the other side. The only way to do this is to multiply both sides by Time/1 to cancel out time on the Displacement/Time side and to make it so Velocity is multiplied by time. So Time/1 x Velocity = Displacement/Time x Time/1. The time and the time on the right side of the equation cancel out to become onem and the new equation is Time x Velocity = Displacement. Try it on paper if it becomes to confusing reading my type. Hope this helps!
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How do you figure out velocity?
Velocity is displacement divided by time. Displacement is different from distance traveled, as displacement states how far you traveled in RELATION to a starting point. The formula for Velocity is ---- v = x / t v = Velocity x = Displacement t = Time velocity is a vector quantity so the direction should also be specified unless it is implicit in the problem. ----
What is velocity and speed?
Speed is a scaler quantity i.e. it has magnitude only without direction. It can be calculated using the formula : speed = distance/time where distance is the total distance travelled from initial position to final position; time is the total time taken to cover this distance. Velocity is a vector quantity i.e. it has magnitude as well as direction. It can be calculated using the formula : velocity = displacement/time displacement is the distance between final position & initial position; time is the total time taken to cover this displacement. for example: if a body starts from some initial point goes to a certain distance x and returns back to the initial position. So the total distance covered is 2x but displacement is 0 (zero) because initial & final position are same. So its speed is 2x/time while velocity is 0/t = 0(zero)
Instantaneous velocity formula?
v = dx/dt (the derivative of 'x' with respect to 't') where 'x' is the displacement of the objectin a given direction, and 't' is time.
I understand distance divided by time is the formula to calculate work How can I show an example to apply the formula?
Work is not defined as distance/time, but rather: work= force x distance Distance divided by time will give you velocity. Displacement (or distance traveled) = velocity x time
How does the total time changes as the total distance increases in case of uniformly accelerated motio n?
the formula that ties displacement (you can think of it as distance in a given direction), velocity, time and acceleration (a) is : s = s0+vt + 1/2at^2 s0 = initial displacement (you can equate to 0, if you start at 0) vt = starting velocity times time (you can equate to 0 if initial velocity is 0) s= final displacement so s=1/2at^2 = (1/2 x a x t x t), so here you end up with a relationship between displacement, acceleration and time. (note: ^2 stands for "to the 2nd power")
