No. Fractions do not include Irrational Numbers. And although there are an infinite number of both rationals and irrationals, there are far more irrational numbers than rationals.
No, the irrationals are more dense.
You have it backwards. Integers are a subset of real numbers.
The real numbers, themselves. Every set is a subset of itself.
Starting at the top, we have the real numbers. The rational numbers is a subset of the reals. So are the irrational numbers. Now some rationals are integers so that is a subset of the rationals. Then a subset of the integers is the whole numbers. The natural numbers is a subset of those.
The natural numbers (ℕ) are a subset of the integers (ℤ) which are a subset of the rational numbers (ℚ) which are a subset of the real numbers (ℝ): ℕ ⊂ ℤ ⊂ ℚ ⊂ ℝ → ℕ ⊂ ℝ and ℤ ⊂ ℝ as well as ℚ ⊂ ℝ
No, the irrationals are more dense.
No because natural numbers are a subset of real numbers
You have it backwards. Integers are a subset of real numbers.
Integers are a subset of rational numbers which are a subset of real numbers which are a subset of complex numbers ...
The real numbers, themselves. Every set is a subset of itself.
Imaginary numbers are not a subset of the real numbers; imaginary means not real.
Starting at the top, we have the real numbers. The rational numbers is a subset of the reals. So are the irrational numbers. Now some rationals are integers so that is a subset of the rationals. Then a subset of the integers is the whole numbers. The natural numbers is a subset of those.
The set of Rational Numbers is a [proper] subset of Real Numbers.
I'm just telling you this ahead of time...but i'm not 100% sure with this answer..: fractions belong in the Rational Numbers
No. Natural numbers are a proper subset of real numbers.
The natural numbers (ℕ) are a subset of the integers (ℤ) which are a subset of the rational numbers (ℚ) which are a subset of the real numbers (ℝ): ℕ ⊂ ℤ ⊂ ℚ ⊂ ℝ → ℕ ⊂ ℝ and ℤ ⊂ ℝ as well as ℚ ⊂ ℝ
Natural numbers are a subset of the set of integers, among others.