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To determine whether a polynomial equation has imaginary solutions, you must first identify what type of equation it is. If it is a quadratic equation, you can use the quadratic formula to solve for the solutions. If the equation is a cubic or higher order polynomial, you can use the Rational Root Theorem to determine if there are any imaginary solutions. The Rational Root Theorem states that if a polynomial equation has rational solutions, they must be a factor of the constant term divided by a factor of the leading coefficient. If there are no rational solutions, then the equation has imaginary solutions. To use the Rational Root Theorem, first list out all the possible rational solutions. Then, plug each possible rational solution into the equation and see if it is a solution. If there are any solutions, then the equation has imaginary solutions. If not, then there are no imaginary solutions.
The classical problem of angle trisection cannot be solved. If it were possible, it would provide the solution to a cubic equation. (-but it isn't and it won't!)
you can have either one or three x-intercepts, but now 2. because two real roots means 1 imaginary root which is not possible since imaginary roots come in pairs (2,4,6,8...)
Put simply, the equation for solving a cubic equation is x2 + 2ax +b = (x+a)2 + b-a2. This leads to x = -a +/- (a2 -b)1/2.
Although there is a method for cubics, there are no simple analytical ways.Sometimes you may be able to use the remainder theorem to find one solutions. THen you can divide the original equation using that solution so that you are now searching for an equation of a lower order. If you started off with a cubic you will now have a quadratic and, if all else fails, you can use the quadratic formula.You could use a graphic method. A cubic musthave a solution although that solution need not be rational. A quartic need no have any.Lastly, you could use a numeric method, such as the Newton-Raphson iteration.