There are 3 odd numbers and 6 possible outcomes so 3/6 or 50% chance it will be odd.
No, usually it is very odd!
Not sure what to make of this question. Two possible answers occur: 1. Yes, 7 is an odd number. 2. The 7th odd number is 13
You forgot to copy the polynomial. However, the Fundamental Theorem of Algebra states that every polynomial has at least one root, if complex roots are allowed. If a polynomial has only real coefficients, and it it of odd degree, it will also have at least one real solution.
9999
An odd-degree function approaches positive infinity in one direction and negative infinity in the other direction so the graph must cross the x-axis at least once, giving it at least one real root.
One possible conjecture: The product is always an odd number. Another possible conjecture: The product is always greater than either of them. Another possible conjecture: Both odd numbers are always factors of the product. Another possible conjecture: The product is never a multiple of ' 2 '. Another possible conjecture: The product is always a real, rational number. Another possible conjecture: The product is always an integer.
A billion (1,000,000,000) is a number that and in great Brittni 12 zeros. This is In between 999,999,999 and 1,000,000,001. This is nether even or odd because it ends with a 0 commonly people say its even because its in between to odd numbers.
No. The sum of any odd number of odd numbers will be an odd number.
If the domain is infinite, any polynomial of odd degree has infinite range whereas a polynomial of even degree has a semi-infinite range. Semi-infinite means that either the range has a real minimum but no maximum (ie maximum = +infinity) or that it has a real maximum but no minimum (ie minimum = -infinity).
the largest odd number is 9
Count the number of zeros in the above number. Suppose that number is n. If n is even, then the answer is ±1 followed by n/2 zeros. If n is odd, then it is ±3.1623 followed by (n-1)/2 zeros, approx.
No it is not possible to get a even number by adding odd and even number. 1+2=3-odd number.3+4=7-odd number.
In answering this question it is important that the roots are counted along with their multiplicity. Thus a double root is counted as two roots, and so on. The degree of a polynomial is exactly the same as the number of roots that it has in the complex field. If the polynomial has real coefficients, then a polynomial with an odd degree has an odd number of roots up to the degree, while a polynomial of even degree has an even number of roots up to the degree. The difference between the degree and the number of roots is the number of complex roots which come as complex conjugate pairs.
Sort of... but not entirely. Assuming the polynomial's coefficients are real, the polynomial either has as many real roots as its degree, or an even number less. Thus, a polynomial of degree 4 can have 4, 2, or 0 real roots; while a polynomial of degree 5 has either 5, 3, or 1 real roots. So, polynomial of odd degree (with real coefficients) will always have at least one real root. For a polynomial of even degree, this is not guaranteed. (In case you are interested about the reason for the rule stated above: this is related to the fact that any complex roots in such a polynomial occur in conjugate pairs; for example: if 5 + 2i is a root, then 5 - 2i is also a root.)
It is not possible. The sum of 7 odd numbers must be odd while 50 is not odd.
Not possible ! If you add an odd number of odd numbers together, the result will ALWAYS be odd !