Make it 2 wide and 21 long and you've got it.
No, it is not possible for a rectangle to have a perimeter of 46 and an area of 42 simultaneously. For a rectangle, the perimeter ( P ) is given by ( P = 2(l + w) ), and the area ( A ) is ( A = l \times w ), where ( l ) is the length and ( w ) is the width. Solving these equations shows that the dimensions needed for these values are inconsistent, meaning no such rectangle exists.
42 square units.
Yes, it is possible to have a perimeter of 34 and an area of 42 for certain shapes. For example, a rectangle can meet these conditions if its dimensions are appropriately chosen. However, such a configuration needs careful calculation to ensure both the perimeter and area requirements are satisfied simultaneously.
what is the perimeter of a 11cm x 10cm rectangle answer 42
There is no limit to the size of the perimeter.
No, it is not possible for a rectangle to have a perimeter of 46 and an area of 42 simultaneously. For a rectangle, the perimeter ( P ) is given by ( P = 2(l + w) ), and the area ( A ) is ( A = l \times w ), where ( l ) is the length and ( w ) is the width. Solving these equations shows that the dimensions needed for these values are inconsistent, meaning no such rectangle exists.
42 square units.
Largest = 86, Smallest 26
Yes, it is possible to have a perimeter of 34 and an area of 42 for certain shapes. For example, a rectangle can meet these conditions if its dimensions are appropriately chosen. However, such a configuration needs careful calculation to ensure both the perimeter and area requirements are satisfied simultaneously.
The perimeter of the rectangle is 42 units
Assuming that it's a rectangle then:- Area = 42*14 = 588 square cm Perimeter = 42+42+14+14 = 112 cm
The perimeter of a rectangle is 42. Meters. The length of the rectangle is threemeter less than twice the width.Mar
Try a rectangle with dimensions of 6 cm and 7 cm, and see what you get.
what is the perimeter of a 11cm x 10cm rectangle answer 42
The dimensions of the rectangle are 3 inches by 14 inches
There is no limit to the size of the perimeter.
To find the least and greatest possible perimeters of a rectangle with an area of 42 square feet, we need to identify the pairs of whole numbers (length and width) that multiply to 42. The pairs are (1, 42), (2, 21), (3, 14), (6, 7). The perimeter is calculated as ( P = 2(\text{length} + \text{width}) ). The least perimeter is from the pair (6, 7), giving ( P = 26 ), while the greatest perimeter is from the pair (1, 42), giving ( P = 86 ).