No, it is not possible for a rectangle to have a perimeter of 46 and an area of 42 simultaneously. For a rectangle, the perimeter ( P ) is given by ( P = 2(l + w) ), and the area ( A ) is ( A = l \times w ), where ( l ) is the length and ( w ) is the width. Solving these equations shows that the dimensions needed for these values are inconsistent, meaning no such rectangle exists.
42 square units.
Make it 2 wide and 21 long and you've got it.
what is the perimeter of a 11cm x 10cm rectangle answer 42
There is no limit to the size of the perimeter.
The dimensions of the rectangle are 3 inches by 14 inches
42 square units.
Largest = 86, Smallest 26
Make it 2 wide and 21 long and you've got it.
The perimeter of the rectangle is 42 units
Assuming that it's a rectangle then:- Area = 42*14 = 588 square cm Perimeter = 42+42+14+14 = 112 cm
The perimeter of a rectangle is 42. Meters. The length of the rectangle is threemeter less than twice the width.Mar
Try a rectangle with dimensions of 6 cm and 7 cm, and see what you get.
what is the perimeter of a 11cm x 10cm rectangle answer 42
The dimensions of the rectangle are 3 inches by 14 inches
There is no limit to the size of the perimeter.
Area of circle = pi*212 = 1385.44236 square cm Area of rectangle = 1385.44236 square cm Lenght of rectangle = 1385.44236/18 = 76.96902 cm Perimeter of rectangle = 2(76.96902)+2(18) = 189.93804 cm
When the linear dimensions of a plane figure are quadrupled, its perimeter is quadrupled, and its area is multiplied by 42 = 16 .