You might want to investigate the rectangle that measures [ 6 by 8 ].
112meters.
28 units
28
28 inches
maybe
28 units
112meters.
28
28 inches
maybe
10
Infinitely many shapes have a perimeter of 28 and an area of 18. A rectangle that has those qualities has one side about 1.432 and the other about 12.568
Rectangle with area 28 m2 and width = 4 m => length = 28/4 = 7m. Then, perimeter = 2*(4+7) = 2*11 = 22 metres.
For example, a 1x15 rectangle and a 2x14 rectangle. They both have perimeter of 32, but they have areas of 15 and 28, respectively.
Of course, there are infinite possible answers to your question, but I will give two possible answers since that is what you asked for. If the rectangle is 1 ft X 48 ft, then the perimeter would be 98 ft. If the rectangle is 6 ft X 8 ft, then the perimeter would be 28 feet.
To find the dimensions of a shape with an area of 49 and a perimeter of 28, we can assume it is a rectangle. Let the length be ( l ) and the width be ( w ). The area can be expressed as ( l \times w = 49 ) and the perimeter as ( 2l + 2w = 28 ). Solving these equations, we find that one possible set of dimensions is ( l = 7 ) and ( w = 7 ), indicating the shape is a square with sides of length 7.
28