maybe
28 inches
You might want to investigate the rectangle that measures [ 6 by 8 ].
Width = 48/8 = 6 Perimeter = (length + width) x 2 = 14 x 2 = 28.
7 x 17
Anything greater than 27.713cm (4 x √48).
28 inches
You might want to investigate the rectangle that measures [ 6 by 8 ].
If the rectangle is a square, the perimeter is 48 cm. If not, there are a lot of possibilities.
2*24
Width = 48/8 = 6 Perimeter = (length + width) x 2 = 14 x 2 = 28.
7 x 17
Of course, there are infinite possible answers to your question, but I will give two possible answers since that is what you asked for. If the rectangle is 1 ft X 48 ft, then the perimeter would be 98 ft. If the rectangle is 6 ft X 8 ft, then the perimeter would be 28 feet.
What are the dimensions of a rectangle that has a perimeter of 56 units and an area of 96 square units
Anything greater than 27.713cm (4 x √48).
The maximum area is attained when the rectangle is, in fact, a square. Since the perimeter = 48 feet, the maximum length for a square = 48/4 = 12 feet. So max area = 122 = 144 square feet.
I thought circumference is only with circles Absolutely correct, but even if you consider the perimeter, which is conceptually similar, there is no answer. A rectangle with an area of 24 could be 4*6 with a perimeter of 20 or it could be 1*24 with a perimeter of 50 or 0.5*48 with a perimeter of 97 etc
No, 12x4 = 48 sq meters. 13x3=39 sq meters.