Q: Is it possible for two rectangles to have the same perimeter and area?

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they dont

thare is only 1 differint rectangles

A rectangle cannot really have the same area and perimeter because an area is a 2-dimensional concept while a perimeter is 1-dimensional.However, you can have rectangles such that the numericalvalue of their area and perimeter are the same.Take any number x > 2 and let y = 2x/(x-2)Then a rectangle with sides of x and y has an area and perimeter whose value is 2x2/(x-2)

10cm by 10cm (perimeter=40cm), 5cm by 20cm (perimeter=50cm), 50cm by 2cm (perimeter=104cm), 100cm by 1cm (perimeter=202cm). All of these rectangles' areas are 100cm2

No, it is not. I'll give you two examples of a rectangle with a perimeter of 1. The first rectangle has dimensions of 1/4x1/4. The area is 1/16. The second rectangle has dimensions of 3/8x1/8. The area is 3/64. You can clearly see that these two rectangles have the same perimeter, yet the area is different.

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they dont

no

Not necessarily. Let's say that there is a circle with the area of 10. Now there is a star with the area of 10. They do not have the same perimeter, do they? That still applies with rectangles. There might be a very long skinny rectangle and a square next to each other with the same area, but that does not mean that they have the same perimeter. Now if the rectangles are congruent then yes.

thare is only 1 differint rectangles

Yes, it can because a 3 by 6 rectangle has the perimeter of 18 and has the area of 18! :)

No. Here are four rectangles with the same perimeter:1 by 6 . . . . . perimeter = 14, area = 62 by 5 . . . . . perimeter = 14, area = 103 by 4 . . . . . perimeter = 14, area = 1231/2 by 31/2 . . perimeter = 14, area = 121/4With all the same perimeter . . . -- The nearer it is to being square, the more area it has.-- The longer and skinnier it is, the less area it has. If somebody gives you some wire fence and tells you to put it uparound the most possible area, your first choice is to put it up ina circle, and your second choice is to put it up in a square. Rectanglesare out, if you can avoid them.

There is no standard relationship between perimeter and area. For example, you can have two rectangles that have the same perimeter, but different area.

A rectangle cannot really have the same area and perimeter because an area is a 2-dimensional concept while a perimeter is 1-dimensional.However, you can have rectangles such that the numericalvalue of their area and perimeter are the same.Take any number x > 2 and let y = 2x/(x-2)Then a rectangle with sides of x and y has an area and perimeter whose value is 2x2/(x-2)

10cm by 10cm (perimeter=40cm), 5cm by 20cm (perimeter=50cm), 50cm by 2cm (perimeter=104cm), 100cm by 1cm (perimeter=202cm). All of these rectangles' areas are 100cm2

It's very easy for two rectangles to have the same area and different perimeters,or the same perimeter and different areas. In either case, it would be obvious toyou when you see them that there's something different about them, and theywould not fit one on top of the other.But if two rectangles have the same area and the same perimeter, then to look at themyou'd swear that they're the same rectangle, and one could be laid down on the otherand fit exactly.

No, it is not. I'll give you two examples of a rectangle with a perimeter of 1. The first rectangle has dimensions of 1/4x1/4. The area is 1/16. The second rectangle has dimensions of 3/8x1/8. The area is 3/64. You can clearly see that these two rectangles have the same perimeter, yet the area is different.

To be perfectly correct about it, a perimeter and an area can never be equal.A perimeter has linear units, while an area has square units.You probably mean that the perimeter and the area are the same number,regardless of the units.It's not possible to list all of the rectangles whose perimeter and area are thesame number, because there are an infinite number of such rectangles.-- Pick any number you want for the length of your rectangle.-- Then make the width equal to (double the length) divided by (the length minus 2).The number of linear units around the perimeter, and the number of square unitsin the area, are now the same number.