No, it is not possible to draw a triangle with angles of 150, 20, and 20 degrees. The sum of the angles in any triangle must equal 180 degrees. In this case, the sum is 150 + 20 + 20 = 190 degrees, which exceeds 180 degrees.
No, it is not possible to draw a triangle with side lengths of 150, 20, and 20. In a triangle, the sum of the lengths of any two sides must be greater than the length of the third side according to the Triangle Inequality Theorem. In this case, 20 + 20 is less than 150, so the given side lengths do not satisfy this theorem, making it impossible to form a triangle.
It would be 30 degrees. it would be 30 degrees because the total of a triangles angles have to equal 180 so: 180 - 150= 30.
Yes. The easiest way to do so is draw a line, then have a right angle at each end, and from the resulting lines draw the final line so it does not form two further right angles. Basically you have 360 degrees to work with. you use 180 degrees up for your two right angles. Now you have 180 degrees left over to work with. you can have one angle be acute (say 30 degrees) and one angle be obtuse (say 150 degrees). This gives you your 2 right angle, non rectangle, quadrilateral.
150 degrees
To figure that out you simply divide 360o by 150: 360o / 150 = 2.4o or 2 2/5o
No, it is not possible to draw a triangle with side lengths of 150, 20, and 20. In a triangle, the sum of the lengths of any two sides must be greater than the length of the third side according to the Triangle Inequality Theorem. In this case, 20 + 20 is less than 150, so the given side lengths do not satisfy this theorem, making it impossible to form a triangle.
No. The interior angles of a triangle must add up to 180° 150° + 10° + 10° = 170° ≠ 180° Therefore a triangle cannot have interior angles of 150°, 10° and 10°
Nope - because the internal angles of a triangle must total 180 degrees !
If you mean angles of 150 degrees, 20 degrees and 20 degrees then it is impossible to construct such a triangle because the angles in any triangle add up to 180 degrees and the angles given add up to 190 degrees.
There are 180 degrees in a triangle, so 180 minus 30 is 150. Since it's an isosceles triangle, that means the other two angles angles are the same, so 150 divided by 2 is 75.
Yes. Since the sum is 180 degrees, that set of three numbers is a perfectly good set of angles for a triangle.
It would be 30 degrees. it would be 30 degrees because the total of a triangles angles have to equal 180 so: 180 - 150= 30.
No. For example, say the two angles are 10° and 20°. Then the other angle is 180°-10°-20°=150° and that is not a right angle. But if the triangle has two equal acute angles of 45 degrees then the 3rd angle must be 90 degrees which will form a right angle triangle.
No problem at all. Here's one: 150 degrees, 25 degrees, 5 degrees.
The largest angle is 105 degrees. The interior angles of any triangle total 180 degrees. Subracting the 30 degrees of the known angle leaves 150 degrees. The remaining 2 angles must total 150 degrees, and be in the proportion 3:7. The proportion can be stated: 3 is to 7 as x is to 150 - x. Cross-multiplying gives the equations: 450 - 3x = 7x 450 = 10x 45 = x So the remaining angles are 45 degrees and 105 degrees. The angles add to 150 degrees and are in the correct proportion, 3:7, since 3 X 15 = 45, and 7 X 15 = 105.
Assuming the set square has angles of 30o 60o and 90o.... You can draw a right angle without any problem. That leaves 60 degrees left to draw so - place the 60 degree corner on the junction of the 90 degrees and draw another line. This gives you a total angle of 150.
The length of the congruent sides is irrelevant. If one of the base angles is 75 deg, the two base angles sum to 150 degrees. Since the sum of all three angles is 180 degrees, the third angle, the vertex angle, must be 180 - 150 = 30 degrees.