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Yes. Consider, if you will, the triangle with sides of 3, 5, and 7 centimeters. Or, perhaps, the trapezoid with sides of 3, 5, 3, and 8 inches. Or even a circle with a perimeter of 55 feet.

However, I believe you're asking if you can have a rectangle with an odd perimeter, without a 1/2 in two of its sides.

The area, you see, is (side)*(adjacent side), so in order for there to be a 1/2 in the area, there would have to be a 1/2 in one of the factors, and the other would have to be odd. And if we imagine a square with sides of 2.25 each, then that makes an odd perimeter of 9, with an area of 81/16 (or 5.0625), which I would consider odd.

And, of course, as you saw above, the square with sides of 2.25 each had no halves in each individual side, and had an odd perimeter. There are many ways to slice the fractions so that there is no 1/2 in any side.

It cannot, however, be done with a whole number, for in a rectangle, two sides absolutely must be equal, such that it is as if you multiply any side length by two. When you multiply a whole number by two, it will inevitably turn out even, regardless of the other factor's oddness or evenness.

Q: Is it possible to have an odd perimeter without a half in the area?

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Area: Find some of the lengths, then cut the L in half and work it out from there. Perimeter: Add all the lengths together.

Perimeter . . . add up the lengths of all three sides. Area . . . multiply (half the length of the base) by (the height).

If it was a square, the answer would be 81 square cm. The area will be the product of two numbers whose sum is half the perimeter.

The base is one third of the perimeter, half of the base times the height is the area.

The area of a circle is equal to the perimeter times half the radius. That is, A = P*r/2

Related questions

If the area is a square, 1/4 of the perimeter is the length of one side. That length squared is the area. The area will be the product of two numbers whose sum is half the perimeter.

Area: Find some of the lengths, then cut the L in half and work it out from there. Perimeter: Add all the lengths together.

The perimeter of that rectangle is 89.6875.

Perimeter . . . add up the lengths of all three sides. Area . . . multiply (half the length of the base) by (the height).

If it was a square, the answer would be 81 square cm. The area will be the product of two numbers whose sum is half the perimeter.

Half an acre = 21780 sq feet.This could have a perimeter of any length greater than (or equal to) 523.16 feet.If the area is in the form of a circle of radius 83.26 feet, it will have the minimum perimeter of 523.16 feet.Or, you can have a square of 147.6 ft giving a perimeter of 590.3 ft,or a rectangle of 150 ft * 145.2 ft - perimeter = 590.4 ftor a rectangle of 100 ft * 217.8 ft - perimeter = 635.6 ftor a rectangle of 10 ft * 2178 ft - perimeter = 4376 ftor a rectangle of 1 ft * 21780 ft - perimeter of = 43562 ftetc, with the perimeter increasing without limit.Or, the area could be circular giving the minim590 feet.

Trick question. 100. :)

The base is one third of the perimeter, half of the base times the height is the area.

Length + width = half the perimeter, but more info eg area, is needed.

Perimeter = diameter x pi. Area = pi x radius2. (The radius is half the diameter.)

The area of a circle is equal to the perimeter times half the radius. That is, A = P*r/2

The answer depends on what characteristic of a half circle you want to calculate: its area or perimeter or something else.