Yes. 3/sqrt(2) is an irrational number and so cannot be round.
It is irrational. Any number that cannot be written as a fraction is irrational. So if the Golden Ratio were rational, instead of a never-ending decimal number, you'd see a fraction. The official measurement is (1+sqrt5)/2. sqrt5 is irrational.
That 's not possible since irrational numbers have infinity digits. All whole numbers are rational.
+sqrt(47) is one possible answer.
An irrational number.
Yes, it is possible only if an irrational number is multiplied with 0.
it is a whole number, and not an integer because you cannot have a negative circumference.
No.
Yes. 3/sqrt(2) is an irrational number and so cannot be round.
An irrational number is one possible answer.
It is irrational. Any number that cannot be written as a fraction is irrational. So if the Golden Ratio were rational, instead of a never-ending decimal number, you'd see a fraction. The official measurement is (1+sqrt5)/2. sqrt5 is irrational.
It certainly is possible. For example, the square root of 2 times the square root of two is equal to two. Another example: pi multiplied by (1/pi) is equal to 1.Ans. 2No, it is not possible. The two 'counterexamples' above involve multiplying the irrational number by another irrational number. But, the question specifies multiplying the irrational number by a whole number other than zero. As long as you obey that restriction you are stuck with an irrational result.
It is not possible to tell. There is no recurring pattern that can be discerned.
It is an irrational number which is the square root of 53
When the rational number is 0.
No, the result is always an irrational number. In more advanced math it is possible to add an infinite amount of rational numbers by way of Taylor Series and get an irrational number. This is how numbers like "Pi" and "e" are derived.
That 's not possible since irrational numbers have infinity digits. All whole numbers are rational.