Yes. the number is 0.2 (or the equivalent 1/5).
8
That word "equals" in there makes it an equation.
That equation has no solution. There is no possible number that's equal to 18 more than itself.
To find the number that, when divided by 2, equals 14, you can set up the equation ( x/2 = 14 ). By multiplying both sides by 2, you get ( x = 28 ). Thus, 28 divided by 2 equals 14.
To find the number for which one fifth equals 18, you can set up the equation ( \frac{1}{5} \times x = 18 ). Multiplying both sides by 5 gives ( x = 90 ). Therefore, the number is 90.
8
When you multiply both sides by a negative number the inequality must be flipped over. You do not do that when multiplying by a positive number.
That word "equals" in there makes it an equation.
by adding, subtracting, dividing, and multiplying.
That equation has no solution. There is no possible number that's equal to 18 more than itself.
To find the number that, when divided by 2, equals 14, you can set up the equation ( x/2 = 14 ). By multiplying both sides by 2, you get ( x = 28 ). Thus, 28 divided by 2 equals 14.
To find the number for which one fifth equals 18, you can set up the equation ( \frac{1}{5} \times x = 18 ). Multiplying both sides by 5 gives ( x = 90 ). Therefore, the number is 90.
To solve the equation "Four less than the quotient of a number and 2 equals 8," we can represent the unknown number as ( x ). The equation can be written as (\frac{x}{2} - 4 = 8). Adding 4 to both sides gives (\frac{x}{2} = 12), and multiplying both sides by 2 results in ( x = 24). Thus, the number is 24.
To find the number that, when divided by seven, equals 15, you can set up the equation ( x / 7 = 15 ). By multiplying both sides by 7, you get ( x = 15 \times 7 ), which simplifies to ( x = 105 ). Therefore, 105 divided by seven equals 15.
That means that multiplying both sides of the equation by the same non-zero number is a valid operation, which often helps you simplify the equation.
99x9999=989901
You can remove parenthesis or bracket by multiplying the number outside, with the number inside the bracket.