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If a number is even (divisible by 2) and divisible by 3, then it must also be divisible by 6.
3924 is divisible by 3 as the digits added together 3+9+2+4=18 is divisible by 3
False. The question consists of two parts: - a number is divisible by 6 if it is divisible by 3? False. It must also be divisible by 2. - a number is divisible by 6 only if it is divisible by 3? This is true but the false part makes the whole statement false.
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