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Lines r and m are parallel or line r is line m continued
line in data is y=-2X+6 The perpendicular line will have a slope of = +1/2 Note : m X m' = -1 , m= slope of line 1 ; m'= slope of perpendicular line to line 1
If we call the slope m we can say that the slope of the perpendicular line is -1/m In this case as the slope, m, is 13 the slope of the perpendicular is -1/13 or -0.07692307692
Negative reciprocals. That is, if one line has slope m (m ≠0), then the perpendicular to it has slope -1/m. If m = 0, the slope of the perpendicular is not defined - the line is of the form x = k.
If the gradient of a line is m, the gradient of a line perpendicular to it (m') is such that mm' = -1, that is: m' = -1/m So for: y = -x - 5 m = -1, so the gradient of a perpendicular line is: m' = -1/-1 = 1 So a general line perpendicular to y = -x - 5 would be: y = x + c A specific line perpendicular to y = -x - 5 at point (xo, -xo-5) on the line is: y - (-xo-5) = 1(x - xo) ⇒ y = x - 2xo - 5