The square root of 64 is +/- 8
Yes, just take its square root. Since it is an integer, 64 is a perfect square. Alternately, since the square of this integer is 64, 64 is a perfect square, by definition.
No. It is a complex number, but that is something different.
sqrt(1) + sqrt(1) + sqrt(64) = +/- 1 +/- 1 +/- 8 positive square root is 10 negative square root is -10 By permutating the +/- it could also be +8, -8 ,
The question is ambiguous. If you meant negative (64 squared), the value is -4096, which is a negative integer. If, instead, you meant (negative 64) squared, the value is +4096, a positive integer.
yes, square root 64 =8 which is integer, rational and real
Yes
The square root of 64 is +/- 8
Yes, just take its square root. Since it is an integer, 64 is a perfect square. Alternately, since the square of this integer is 64, 64 is a perfect square, by definition.
Rational. It is a perfect square with answer exactly 8The square root of 64 is the integer 8 (8 x 8 = 64) so it is rational.
The square root of negative 64 isn't even a real number. In math and engineering, it's called an "imaginary number".
Since 8x8 = 64 and (-8)x(-8) is also = 64
No. It is a complex number, but that is something different.
That simply means that there is both a positive and a negative number which, when squared, gives you 64.
square root of 64 is 8
The square root of 64 is 8
sqrt(1) + sqrt(1) + sqrt(64) = +/- 1 +/- 1 +/- 8 positive square root is 10 negative square root is -10 By permutating the +/- it could also be +8, -8 ,