11 and 110 are not relatively prime because they have 11 as a common factor.
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11 is a prime number. For it to be relatively prime, it needs to be compared to another integer.
Yes, 11 and 51 are relatively prime.
110. LCM is "Least common multiple," meaning the smallest number divisible by each of the arguments. 110/11=10, 110/10=11, 110/22=5 implies 10, 11, and 22 all divide 110. 110 is the smallest such number because its prime factorization is 2*5*11. 2 and 5 are necessary because 10 must divide the answer; likewise 11 because 11 must divide the answer (remember 11 is prime).
110 is an even number; therefore, it's divisible by 2. Indeed, 110/2 = 55. 55 ends with the number 5, and so must be divisible by 5, which it is; 55/5 = 11. We now have three factors for 110: 2, 5, and 11. All three of those numbers are prime numbers, so we're done. Thus the prime factorization of 110 is 2 X 5 X 11.
The prime factorization of 110 is 2 x 5 x 112 x 5 x 11 = 110As a product of its prime factors: 2*5*11 = 110