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110 is an even number; therefore, it's divisible by 2. Indeed, 110/2 = 55. 55 ends with the number 5, and so must be divisible by 5, which it is; 55/5 = 11. We now have three factors for 110: 2, 5, and 11. All three of those numbers are prime numbers, so we're done. Thus the prime factorization of 110 is 2 X 5 X 11.

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2 x 5 x 11

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8y ago
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Q: Find the prime factorization of the number 110?
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