110 is an even number; therefore, it's divisible by 2. Indeed, 110/2 = 55. 55 ends with the number 5, and so must be divisible by 5, which it is; 55/5 = 11. We now have three factors for 110: 2, 5, and 11. All three of those numbers are prime numbers, so we're done. Thus the prime factorization of 110 is 2 X 5 X 11.
It is: 2*5*11 = 110
The prime factorization of 110 is 2 x 5 x 112 x 5 x 11 = 110As a product of its prime factors: 2*5*11 = 110
110 = 21 x 51 x 111
110 55,2 11,5,2 2 x 5 x 11 = 110
The prime factors of 110 are 2x5x11.
110 = 2 x 5 x 11
A prime factor = prime number which can be divided into the given number with no remainder ie 2, 5, 11
To find the least common multiple (LCM) of two numbers, you first need to find the prime factorization of each number. The prime factorization of 78 is 2 x 3 x 13, and the prime factorization of 110 is 2 x 5 x 11. Then, you take the highest power of each prime factor that appears in either number. The LCM of 78 and 110 is therefore 2 x 3 x 5 x 11 x 13, which equals 4290.
It is: 2*5*11 = 110
The tree for 110 is: 55 & 2. 2 is prime. Then 5 & 11. They are both prime.
2 x 5 x 11 = 110
2 x 5 x 11 = 110
2×5×11
110 55,2 11,5,2
The prime factorization of 110 is 2 x 5 x 112 x 5 x 11 = 110As a product of its prime factors: 2*5*11 = 110
110 = 21 x 51 x 111
2 x 5 x 11 = 110