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BODMAS would say that addition is before subtraction.

There is a main code "DMAS", which prove that:

D:Divide

M:Multiplication

A:Addition

S:Subtraction

It proves that Addition is before Subtraction.

HOPE U LIKE THAT:)

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Q: Is order of subtraction and addition performed last?
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Continue Learning about Math & Arithmetic

What are the two last operations in the order of operations?

The last two operations in P.E.M.D.A.S are 'addition' and 'subtraction'.


What is the last step in the order of operations?

Subtraction. Remeber it's PEMDAS. Parenthesis, Exponent, Multiplication, Division, Addition and Subtraction.


How are addition multiplication division and subtraction different?

The 'Order of Operations' ensures that arithmetic and maths is done in the correct order: 1 Parentheses (brackets) 2 Exponents (Powers and Roots) 3 Multiplication and Division 4 Addition and Subtraction Memory aid is 'PEMDAS' Note: In the calculation below, the parentheses are done first, then the multiplication done last. (8+2)×(9÷3)=30


How does order operation involving the set or real number accept as?

Order of operations. Parenthesis (including all grouping symbols) are done 1st. Exponents or their equivalents (radicals, logs) are done next. Multiplication and division are done 3rd (from left to right). Addition and subtraction are dome last again, from left to right.


Why does the commutative and associative properties don't hold true for subtraction and division but the identity properties do?

Consider the main operations to be addition and multiplication. In that case, subtraction is defined in terms of addition, for example, a - b = a + (-b) (where the last "-b" refers to the additive inverse of b), while a / b = a times 1/b (where 1/b is the multiplicative inverse of b). Now, assuming that commutative, etc. properties hold for addition and multiplication, check what happens with a subtraction. That should clarify everything. For example: a - b = a + (-b) whereas: b - a = b + (-a) which happens NOT to be the same as a - b, but rather its additive inverse.