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Is point (23) on the line represented by the equation x-2y-4?
To determine if the point (23) lies on the line given by the equation ( x - 2y - 4 = 0 ), we need to substitute the coordinates of the point into the equation. Since (23) is not a complete coordinate point (it lacks a y-value), we cannot evaluate it against the line's equation. If a full coordinate point (like (23, y)) is provided, we could check if it satisfies the equation.
What is the equation of a line with a slope of 23 which contains the point 04?
If you mean a slope of 23 and a point of (0, 4) then the equation is y = 23x+4
What is the equation of straight line which passes threw the point (-23) and parallel to the line x-y7?
If you mean: the point of (-2, 3) and equation of x-y = 7 then the parallel equation works out as y = x+5
How do you write the equation of a line that is parallel to y23x-2 and passes through -47?
To write the equation of a line that is parallel to ( y = 23x - 2 ), you need to use the same slope, which is 23. The point through which the line passes is (-4, 7). You can use the point-slope form of the equation of a line: ( y - y_1 = m(x - x_1) ). Substituting in the slope (23) and the point (-4, 7), the equation becomes ( y - 7 = 23(x + 4) ), which simplifies to ( y = 23x + 99 ).
What is the equation of the line that has a slope of 6 and passes through the point (-35)?
If you mean a slope of 6 and point of (-3, 5) then the equation is: y = 6x+23
Is point (23) on the line represented by the equation x-2y-4?
To determine if the point (23) lies on the line given by the equation ( x - 2y - 4 = 0 ), we need to substitute the coordinates of the point into the equation. Since (23) is not a complete coordinate point (it lacks a y-value), we cannot evaluate it against the line's equation. If a full coordinate point (like (23, y)) is provided, we could check if it satisfies the equation.
What is the equation of a line with a slope of 23 which contains the point 04?
If you mean a slope of 23 and a point of (0, 4) then the equation is y = 23x+4
What is the equation of straight line which passes threw the point (-23) and parallel to the line x-y7?
If you mean: the point of (-2, 3) and equation of x-y = 7 then the parallel equation works out as y = x+5
How do you write the equation of a line that is parallel to y23x-2 and passes through -47?
To write the equation of a line that is parallel to ( y = 23x - 2 ), you need to use the same slope, which is 23. The point through which the line passes is (-4, 7). You can use the point-slope form of the equation of a line: ( y - y_1 = m(x - x_1) ). Substituting in the slope (23) and the point (-4, 7), the equation becomes ( y - 7 = 23(x + 4) ), which simplifies to ( y = 23x + 99 ).
What is the equation of the line that has a slope of 6 and passes through the point (-35)?
If you mean a slope of 6 and point of (-3, 5) then the equation is: y = 6x+23
What is a equation of a line slope of 4 and passes through the point (-47)?
If you mean a point of: (-4, 7) and a slope of 4 Then the equation works out as: y = 4x+23
Perpendicular line of y23x 5?
To find the equation of a line that is perpendicular to ( y = 23x + 5 ), we first identify the slope of the given line, which is 23. The slope of a line that is perpendicular to it is the negative reciprocal, so it would be ( -\frac{1}{23} ). If we have a point through which the perpendicular line passes, we can use the point-slope form ( y - y_1 = m(x - x_1) ) to write the equation, where ( m = -\frac{1}{23} ).
What is the equation of the line that passes through the following points in point slope form. (-23)(2-3)?
Slope=8 point=(-7,3)
What is the equation for a line with a slope of 0 that passes through (-23) what will this line look like?
It is: y = -23 which will be straight horizontal line parallel to the x axis
What is the slope of this equation y equals 20-3X?
23
What is the point of intersection of the equation 4y equals 5x with the line joining the points 13 17 and 19 23 on the Cartesian plane showing work?
Points of line: (13, 17) and (19, 23) Its slope: 1 Its equation: y = x+4 => y-x = 4 Multiply all terms by 4: 4y-4x = 16 Equation of: 4y = 5x => 4y-5x = 0 Subtacting equations: x = 16 By substitution point of intersection is at: (16, 20)
What is the slope of the line with equation 17x plus 23y equals 25?
-17/23 and the intercept is 25/23
