Q: Is point (2-3) on the line represented by the equation x - 2y -4?

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If you mean a slope of 23 and a point of (0, 4) then the equation is y = 23x+4

If you mean: the point of (-2, 3) and equation of x-y = 7 then the parallel equation works out as y = x+5

If you mean a slope of 6 and point of (-3, 5) then the equation is: y = 6x+23

If you mean a point of: (-4, 7) and a slope of 4 Then the equation works out as: y = 4x+23

Slope=8 point=(-7,3)

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If you mean a slope of 23 and a point of (0, 4) then the equation is y = 23x+4

If you mean: the point of (-2, 3) and equation of x-y = 7 then the parallel equation works out as y = x+5

If you mean a slope of 6 and point of (-3, 5) then the equation is: y = 6x+23

If you mean a point of: (-4, 7) and a slope of 4 Then the equation works out as: y = 4x+23

Slope=8 point=(-7,3)

It is: y = -23 which will be straight horizontal line parallel to the x axis

23

-17/23 and the intercept is 25/23

Points of line: (13, 17) and (19, 23) Its slope: 1 Its equation: y = x+4 => y-x = 4 Multiply all terms by 4: 4y-4x = 16 Equation of: 4y = 5x => 4y-5x = 0 Subtacting equations: x = 16 By substitution point of intersection is at: (16, 20)

If you mean: y = 12x-23 then the slope is 12 and the y intercept is -23

This is the equation of a straight line. It can be rearranged as {y = (1/3)*x - 23/3}

Points: (0, 3) and (5, 23) Slope: 4 Equation: y = 4x+3