If you mean a slope of -5 and a point of (6, 3) then the equation is y = -5x+33
The equation of the line will also depend on its slope which has not been given and so an answer is not possible.
The straight line equation is: y = mx+c whereas m is the slope and c is the y intercept
The straight line equation for a line with a slope of 6 that goes through (1,2) works out as: y = 6x-4
Equation: y-3 = -5(x-6) => y = -5x+33
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
If you mean a slope of -5 and a point of (6, 3) then the equation is y = -5x+33
The equation of the line will also depend on its slope which has not been given and so an answer is not possible.
Slope: -5 Points: (6, 3) Equation: y = -5x+33
The straight line equation is: y = mx+c whereas m is the slope and c is the y intercept
Slope: -3 Point: (4, -5) Equation: y = -3x+7
The straight line equation for a line with a slope of 6 that goes through (1,2) works out as: y = 6x-4
Point: (2, -1) Slope: -5 Equation: y = -5x+9
Equation: y-3 = -5(x-6) => y = -5x+33
Equation: y-3 = -5(x-6) => y = -5x+33
Equation: y-3 = -5(x-6) => y = -5x+33
Equation: y-3 = -5(x-6) => y = -5x+33