Q: What is the equation of a line with a slope of 23 which contains the point 04?

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If you mean a slope of -5 and a point of (6, 3) then the equation is y = -5x+33

The equation of the line will also depend on its slope which has not been given and so an answer is not possible.

The straight line equation is: y = mx+c whereas m is the slope and c is the y intercept

The straight line equation for a line with a slope of 6 that goes through (1,2) works out as: y = 6x-4

Equation: y-3 = -5(x-6) => y = -5x+33

Related questions

Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).

If you mean a slope of -5 and a point of (6, 3) then the equation is y = -5x+33

The equation of the line will also depend on its slope which has not been given and so an answer is not possible.

Slope: -5 Points: (6, 3) Equation: y = -5x+33

The straight line equation is: y = mx+c whereas m is the slope and c is the y intercept

Slope: -3 Point: (4, -5) Equation: y = -3x+7

The straight line equation for a line with a slope of 6 that goes through (1,2) works out as: y = 6x-4

Point: (2, -1) Slope: -5 Equation: y = -5x+9

Equation: y-3 = -5(x-6) => y = -5x+33

Equation: y-3 = -5(x-6) => y = -5x+33

Equation: y-3 = -5(x-6) => y = -5x+33

Equation: y-3 = -5(x-6) => y = -5x+33