The square root of 4, denoted as √4, is not an irrational number; it is a rational number because it equals 2. A rational number can be expressed as the quotient of two integers, and in this case, 2 can be represented as 2/1. Therefore, √4 is a whole number and not irrational.
No. Sqrt(-4) contains a radical but it not irrational; it is imaginary.
Yes.
√ 5 is an irrational number. Any square root of a prime number is irrational.
No they are not. The numbers Pi and e are irrational and are not radicals. There are many others.
Yes, the square root of 40, or radical 40, is an irrational number. This is because it cannot be expressed as a fraction of two integers. The square root of 40 simplifies to (2\sqrt{10}), and since (\sqrt{10}) is also irrational, the entire expression remains irrational.
No. Sqrt(-4) contains a radical but it not irrational; it is imaginary.
Yes.
The square root (radical) of 5 is about 2.2361 (an irrational number)
√ 5 is an irrational number. Any square root of a prime number is irrational.
No. Radical(1.21) = 1.1, for example, is rational.
The root of an irrational doesn't have any specific name - radical pi is just radical pi, for example.
No they are not. The numbers Pi and e are irrational and are not radicals. There are many others.
Sqrt(4) is +/- 2 so it is rational, not irrational. The question, therefore, makes no sense.
Yes, the square root of 40, or radical 40, is an irrational number. This is because it cannot be expressed as a fraction of two integers. The square root of 40 simplifies to (2\sqrt{10}), and since (\sqrt{10}) is also irrational, the entire expression remains irrational.
If the symbol preceding the 61 is intended to be a radical sign, the answer is yes. If it is not a radical, it depends on the value of v.
No. 4 over 4, or 1 whole, is not an irrational number. It can be written as a simple fraction, 4/4, so it is not an irrational number.
no, because the root of a number that isn't a perfect square is irrational