The presentation of an even number is 2n (we can use any letter, such as 2m or 2r) Let the first even number be 2n and the second number be 2m. So we have, 2n + 2m = 2(n + m) let n + m = r, then by substituting r for n + m we have = 2r Since 2r represents an even number, then we can say that when are adding two even numbers we obtain another even number.
2r + 5 - - 1 When simplified: 2r + 6
2r + 4 or 2*(r+2)
9r-1?
It is not correct to say that 8 plus 2 8r-2r 4 3r plus 2 r = 0
The presentation of an even number is 2n (we can use any letter, such as 2m or 2r) Let the first even number be 2n and the second number be 2m. So we have, 2n + 2m = 2(n + m) let n + m = r, then by substituting r for n + m we have = 2r Since 2r represents an even number, then we can say that when are adding two even numbers we obtain another even number.
2r + 5 - - 1 When simplified: 2r + 6
2r + 4 or 2*(r+2)
|2r + 9| = 5 So 2r + 9 = 5 or 2r + 9 = -5 so that 2r = -4 or 2r = -14 r = -2 or r = -7
2r + 7r - 6t - r + 7t = 8r + t
4r+4g
9r-1?
It is not correct to say that 8 plus 2 8r-2r 4 3r plus 2 r = 0
5(2r + 5)
r -31
It is 4r + 12s
10+r = 2r Subtract r from both sides:- r = 10