2r + 4 or 2*(r+2)
2r + 5 - - 1 When simplified: 2r + 6
Solving for r: 16r2+18r+5=0 (2r+1)(8r+5)=0 2r+1=0 and 8r+5=0 2r=-1 .......... 8r=-5 r= -1/2 ........ r= -5/8
(r + 1)(2r + 5)
2r-1=9 2r =10 r =5
9r-1?
|2r + 9| = 5 So 2r + 9 = 5 or 2r + 9 = -5 so that 2r = -4 or 2r = -14 r = -2 or r = -7
5(2r + 5)
5
4r2-25 = (2r)2-52 = (2r-5)(2r+5)
2r + 7r - 6t - r + 7t = 8r + t
4r+4g
Divide all terms by 5 and then it factors out as: (2r-9)(r+6)
5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 9 + 9 + 9 + 1 - 1 - 1 - 1 - 1 - 1 - 1 - 1 - 1 - 1 - 1 - 1 - 1 - 1 = 43
1)5r+7=13+2r+3r 2)5r+7=13+5r 3)5r's cancel 7=13 4)Subtract thirteen on both sides 7 =13 -13 -13 5)Answer is no solution because -6 doesn't equal to 0. -6=0 NO SOLUTION!!! Have fun with math!
10+r = 2r Subtract r from both sides:- r = 10
r -31
It is 4r + 12s